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Kobotan [32]
3 years ago
6

make a function machine for the expression 10-5x use it to find ordered pairs x=3, x= -y, x =0.25, and x= 3/4

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
7 0

Answer:

  • (3, -5)
  • (2.5, -2.5)
  • (0.25, 8.75)
  • (3/4, 6 1/4)

Step-by-step explanation:

We assume that "make a function machine" means to program a spreadsheet or calculator to calculate values of the function for different inputs. Just about any graphing calculator or spreadsheet is a suitable platform. Attached is a screeenshot using the free Desmos online graphing calculator.

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Identify the values that will make this equation true (x+1)(x+2)=0
liubo4ka [24]

Answer:

-1, -2

Step-by-step explanation:

Since multiplication by 0 will result in 0, any value of x resulting in 0

(-1+1)(-1+2)=0

0x1=0

(-2+1)(-2+2)=0

-1x0=0

3 0
3 years ago
8. Five times a number minus 4 is six.​
Semmy [17]

Answer:

2

Step-by-step explanation:

Let n equal that number.

5n-4=6

5n=10

n=2

7 0
3 years ago
Read 2 more answers
Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu
olchik [2.2K]

Answer:

a) s^2 =30^2 =900

b) \frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

c) 23.818 \leq \sigma \leq 41.112

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in  the variability in the number of rooms occupied per day during a particular season of the  year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per  day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

s^2 =30^2 =900

Part b

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom are given by:

df=n-1=20-1=19

Since the Confidence is 0.90 or 90%, the significance \alpha=0.1 and \alpha/2 =0.05, the critical values for this case are:

\chi^2_{\alpha/2}=30.144

\chi^2_{1- \alpha/2}=10.117

And replacing into the formula for the interval we got:

\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

Part c

Now we just take square root on both sides of the interval and we got:

23.818 \leq \sigma \leq 41.112

5 0
4 years ago
Please help due asap
Nadusha1986 [10]
Answer:5
Explanation:Pythagorean Theorem
4 0
2 years ago
11c - 2d = -2 <br> c + 8d = 8 <br> using the substitution method
Darya [45]
<span>A) 11c - 2d = -2
B) c + 8d = 8
</span><span>B) c  = 8 - 8d then substitute this into A)

</span><span>A) 88 -88d - 2d = -2
A) 90 = 90d
d = 1
c = 0

</span>
4 0
3 years ago
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