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Kobotan [32]
3 years ago
6

make a function machine for the expression 10-5x use it to find ordered pairs x=3, x= -y, x =0.25, and x= 3/4

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
7 0

Answer:

  • (3, -5)
  • (2.5, -2.5)
  • (0.25, 8.75)
  • (3/4, 6 1/4)

Step-by-step explanation:

We assume that "make a function machine" means to program a spreadsheet or calculator to calculate values of the function for different inputs. Just about any graphing calculator or spreadsheet is a suitable platform. Attached is a screeenshot using the free Desmos online graphing calculator.

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Zielflug [23.3K]

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Perpendicular lines.

Step-by-step explanation:

They are called perpendicular lines.

If the slope of one line is m them the slope of the other is -1/m.

5 0
3 years ago
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5+3r=5r-19(if there is no solution,type in ''no solution'')r= Answer
TEA [102]

Answer: 12 = r

Step-by-step explanation: When we have this kind of a setup, we want to put our variables together on one side of the equation and our numbers together on the other side of the equation.

First, let's put our variables on the right side by subtracting 3r from both sides of the equation. That gives us 5 = 2r - 19.

Now we can move our numbers to the left by adding 19 to both sides of the equation and we get 24 = 2r.

Divide both sides by 2 and 12 = r

Note:

Don't just do this problem in your head. It's extremely important to develop the habit of putting all your steps down on paper or digitally. It will really pay off for you down the line.

4 0
3 years ago
Use the four-step definition of the derivative to find f'(x) if f(x) = −4x^3 −1.
guapka [62]

\stackrel{de finition \textit{ of a derivative as a limit}}{\lim\limits_{h\to 0}~\cfrac{f(x+h)-f(x)}{h}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{[-4(x+h)^3-1]~~ - ~~[-4x^3-1]}{h} \\\\\\ \cfrac{[-4(x^3+3x^2h+3xh^2+h^3)-1]~~ ~~+4x^3+1}{h} \\\\\\ \cfrac{[-4x^3-12x^2h-12xh^2-4h^3-1]~~ ~~+4x^3+1}{h} \\\\\\ \cfrac{-4x^3-12x^2h-12xh^2-4h^3-1+4x^3+1}{h}\implies \cfrac{-12x^2h-12xh^2-4h^3}{h}

\cfrac{h(-12x^2-12xh-4h^2)}{h}\implies -12x^2-12xh-4h^2 \\\\\\ \lim\limits_{h\to 0}~-12x^2-12xh-4h^2\implies \lim\limits_{h\to 0}~-12x^2-12x(0)-4(0)^2 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \lim\limits_{h\to 0}~-12x^2~\hfill

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2 years ago
Scott started a test at 3:45 PM and finished it at 4:32 Pm.
schepotkina [342]

Answer:

47min.

Step-by-step explanation:

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Solve for A. Please help and thank u
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Answer:

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