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IRISSAK [1]
3 years ago
13

Kelly needs to order lunch for orders 6 people at a business meeting. Her menu choices are chicken salad for a cost of $5 per pe

rson and egg salad for a cost of $4 per person. She only had$28 to spend. More people want chicken salad. Write and graph one equation in a system for this situation.
Mathematics
1 answer:
nirvana33 [79]3 years ago
5 0
Ok , with that information we can write the equations
x + y = 6
5x + 4y = 28

Where x = how many people ordered chicken
and y = how many people ordered egg salad

Through elimination , we can set one of the variables in both equations equal so we can eliminate it :

(4)x + (4)y = (4)6
5x + 4y = 28

4x + 4y = 24. equation 1
5x + 4y = 28. equation 2

Now we can subtract the second equation by the first equation and isolate one variable:
equation 2 - equation 1

5x - 4x + 4y - 4y = 28 - 24

x = 4

Now that we discovered our x value ( How many people ordered chicken salad ) , we can apply it to one of the equations and discover y ( how many people ordered egg salad)

x + y = 6
x= 4
4 + y = 6

We can shift 4 to the other side of the equation by subtracting 4 from both sides of the equation:
4 - 4 + y = 6 - 4
y = 2

x=4 and y=2

So the awnser is :
4 people ordered chicken salad and 2 people ordered egg salad!

I hope you understood my brief explanation!!

p.s if you want to know how to use another method to solve these problems ( Substition) , just let me know in a comentary down here
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Answer:

a. 11.26 % b. 6.76 %. It appears so since 6.76 % ≠ 15 %

Step-by-step explanation:

a. This is a binomial probability.

Let q = probability of giving out wrong number = 15 % = 0.15

p = probability of not giving out wrong number = 1 - q = 1 - 0.15 = 0.75

For a binomial probability, P(x) = ⁿCₓqˣpⁿ⁻ˣ. With n = 10 and x = 1, the probability of getting a number wrong P(x = 1) = ¹⁰C₁q¹p¹⁰⁻¹

= 10(0.15)(0.75)⁹

= 1.5(0.0751)

= 0.1126

= 11.26 %

b. At most one wrong is P(x ≤ 1) = P(0) + P(1)

= ¹⁰C₀q⁰p¹⁰⁻⁰ + ¹⁰C₁q¹p¹⁰⁻¹

= 1 × 1 × (0.75)¹⁰ + 10(0.15)(0.75)⁹

= 0.0563 + 0.01126

= 0.06756

= 6.756 %

≅ 6.76 %

Since the probability of at most one wrong number i got P(x ≤ 1) = 6.76 % ≠ 15 % the original probability of at most one are not equal, it thus appears that the original probability of 15 % is wrong.

3 0
3 years ago
"Raju's father age is 5 years more than three times of Raju's age. Raju's father age is 50 years."​
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Let rajus age be x

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ATQ

\\ \bull\tt\longmapsto 3x+5=50

\\ \bull\tt\longmapsto 3x=50-5

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\\ \bull\tt\longmapsto x=\dfrac{45}{3}

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Step-by-step explanation:

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