Question

Indicate in standard form the equation of the line passing through the given points G (4,6) H (1,5)

Answer 1

First, find the slope (m) = $\frac{y2 - y1}{x2 - x1}$ = $\frac{5 - 6}{1 - 4}$ = $\frac{-1}{-3}$ = $\frac{1}{3}$

Now plug in ONE of the points and the slope into the point-slope equation:

y - y₁ = m(x - x₁); where (x₁, y₁) is the chosen point.

y - 5 = $\frac{1}{3}$(x - 1) (I used (1,5) as the chosen point)

3(y - 5) = x - 1

3y - 15 = x - 1

3y -14 = x

-14 = x - 3y → x - 3y = -14

Answer: x - 3y = -14