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Nikitich [7]
3 years ago
5

stuart has some 2-ounce, 3 -ounce, and 4-ounce weights. how many different ways can stuart combine the weights to make a total o

f 12 ounces?
Mathematics
1 answer:
Alexxx [7]3 years ago
8 0
2 + 2 + 2 + 2 + 2 + 2 = 12

2 + 2 + 2 + 2 + 4 = 12

2 + 2 + 4 + 4 = 12

4 + 4 + 4 = 12

3 + 3 + 3 + 3 = 12

3 + 3 + 2 + 2 + 2 = 12

3 + 3 + 4 + 2 = 12

I get 7 ways.
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Simplity 2 – 32+52-8.​
Elza [17]

Answer:

14

Step-by-step explanation:

2-32+52-8=-30+52-8=22-8=14

7 0
3 years ago
Read 2 more answers
Which of the following equations have infinitely many solutions? 
Bond [772]

Answer:

Equation I , II and V.

Step-by-step explanation:

Number II:L

0.5(8x + 4) = 4x + 2    Distributing the 0.5 over the parentheses:

4x + 2 = 4x + 2

The 2 sides of this equation are identical so we can make x any value to fit this identity. That is there are Infinite Solutions.

I and V are also included:

I: 12x + 24 = 12x + 24.

V left side = right side.

8 0
4 years ago
HELP DUE IN 2 HOURSSS
tekilochka [14]

Answer:

1.05 miles per hour

Step-by-step explanation:

m = y2 - y1/ x2 - x1 (It doesn't matter which you choose to be y2 and y1, just make it consistent)

m = 4.2 - 2.1/ 4 - 2

m = 2.1 / 2

m = 1.05

6 0
3 years ago
Can anyone do 4,5 and 6 for me plz
cricket20 [7]

For  question 4, sinA =\frac{a}{c}, cosA= \frac{b}{c}, tan B = \frac{b}{a}, sin J = \frac{j}{l}, cosK = \frac{j}{l}, tanK = \frac{k}{j}.

Question 5. Option a and question 6. Option j

Step-by-step explanation:

Step 1:

The three basic formula needed to solve these questions are:

sin\theta = \frac{oppositeside}{hypotenuse} , cos\theta = \frac{adjacentside}{hypotenuse}, tan\theta= \frac{opposite side}{adjacent side}.

Step 2:

Using the above formula, we solve the following values

sinA = \frac{oppositeside}{hypotenuse}  =\frac{a}{c}.

cosA = \frac{adjacentside}{hypotenuse} = \frac{b}{c}.

tanB= \frac{opposite side}{adjacent side}= \frac{b}{a}.

sinJ = \frac{oppositeside}{hypotenuse} = \frac{j}{l}.

cosK = \frac{adjacentside}{hypotenuse}= \frac{j}{l}.

tanK= \frac{opposite side}{adjacent side}= \frac{k}{j}.

Step 3:

For question 5, The triangle's angle = 23°, opposite side = BC inches and hypotenuse = 4 inches.

sin\theta= \frac{opposite side}{hypotenuse}. sin 23^{\circ}= \frac{BC}{4}, sin23^{\circ} = 0.3907,BC = (0.3907)(4) = 1.5628.

SO BC is 1.5628 inches, rounding this off to the nearest tenth, we get BC = 1.6 inches which is option a.

Step 4:

For question 6, The triangle's angle = 50°, opposite side = QR m the adjacent side = 8.1 m.

tan\theta= \frac{opposite side}{adjacentside}. tan 50^{\circ}=\frac{QR}{8.1}, tan50^{\circ} = 1.1917,QR = (1.1917)(8.1) = 9.65277

SO QR is 9.65277 meters, rounding this off to the nearest tenth, we get QR = 9.7 inches which is option j.

7 0
3 years ago
An unknown number y is 10 more than an unknown number x. The number y is also x less than 3. The equations to find x and y are s
Dominik [7]

Answer:

a. add the equations to eliminate x

Step-by-step explanation:

this is called process of elimination

8 0
3 years ago
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