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deff fn [24]
3 years ago
13

The probability of drawing jacks from a deck of cards in ten different trials where cards are replaced after each trial

Mathematics
1 answer:
Gelneren [198K]3 years ago
4 0
Sample space={52 cards} = All possible outcomes
Favorable event {4 Jacks}
Important info: CARD is replaced after each trial

P(drawing Jack) = 4/52 = 1/13 = 0.0769 
It will always be 0.0769 whatever the number of trials

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For this case we propose a rule of three. We assume that the excess water received was in one day. So:

\frac {3} {4} cup ------> 100%

x ----------------------------> 25%

Where "x" represents excess water.

x = \frac {25 * \frac {3} {4}} {100}\\x = \frac {\frac {75} {4}} {100}\\x = \frac {75} {400}\\x = \frac {15} {80}\\x = \frac {3} {16}

Thus, the excess water is \frac {3} {16}cups.

Then, in one day you receive in total:

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Answer:

\frac {15} {4} cups of water

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Answer:

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Given a system of linear equations; explain your strategy for solving the system, show the math required to solve the problem, a
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<em><u>Solution:</u></em>

<em><u>Given equations are:</u></em>

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We can solve the equations by substitution method

In eqn 1, we have y equals 3x - 3

If we substitute this in place of y in eqn 2, we can get value of "x"

Substitute eqn 1 in eqn 2

3x - 3 = 2x - 1

Move the variables to one side and constants to other side

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