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Maksim231197 [3]
3 years ago
12

What is the area of this figure? Enter your answer in the box. ___m²

Mathematics
1 answer:
ra1l [238]3 years ago
6 0
Well first you got figure out the formulas for the 2 triangles and the trapezoid.

The triangles formula for area is: A=b*h/2

The trapezoids formula for area is: A=1/2(b1+b2)*h

After you found the formulas you got to plug in the numbers.

For the first triangle it’s: A=9*5/2

The second triangle it’s: A=8*8/2

The trapezoid it’s: A=1/2(9+8)*5

After you plug in the numbers you have to solve the areas.

So the first triangle is: 9*5/2=9*5=45/2=22.5

So the area of the first triangle is 22.5

Then you have to solve the second triangle.

The second triangle: 8*8/2=8*8=64/2=32

So the area of the second triangle is 32

After solving the second triangle you have to solve the trapezoid.

Trapezoid: 1/2(9+8)*5=9+8=17=1/2(17)*5=17*5=85/2=
42.5

The area of the trapezoid is 42.5

After solving all of the shapes you have to add up all of the areas to get your full area.

22.5+32+42.5=22.5+42.5=65+32=97

So the area of the whole thing is 97

Hope this helps you!!!! Have a nice day!!!!
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Semmy [17]
Remark
The key step is just to subtract 5 from both sides. The pointed of the inequality still points away from the variable and towards the number. As long as that remains true, the correct answer can be found.

Solution
2.7 ≤ b + 5  Subtract 5 from both sides.
2.7 - 5 ≤ b
- 2.3 ≤ b      Write with the variable on the left.
b ≥ - 2.3  <<<< answer  
6 0
3 years ago
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snow_lady [41]

Answer:

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Step-by-step explanation:

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2 years ago
What are the fourth roots of 6+6√(3i) ?
Helen [10]

Answer:

Step-by-step explanation:

The genral form of a complex number in rectangular plane is expressed as z = x+iy

In polar coordinate, z =rcos ∅+irsin∅ where;

r is the modulus = √x²+y²

∅ is teh argument = arctan y/x

Given thr complex number z = 6+6√(3)i

r = √6²+(6√3)²

r = √36+108

r = √144

r = 12

∅ = arctan 6√3/6

∅ = arctan √3

∅ = 60°

In polar form, z = 12(cos60°+isin60°)

z = 12(cosπ/3+isinπ/3)

To get the fourth root of the equation, we will use the de moivres theorem; zⁿ = rⁿ(cosn∅+isinn∅)

z^1/4  = 12^1/4(cosπ/12+isinπ/12)

When n = 1;

z1 =  12^1/4(cosπ/3+isinn/3)

z1 = 12^1/4cis(π/3)

when n = 2;

z2 = 12^1/4(cos2π/3+isin2π/3)

z2 = 12^1/4cis(2π/3)

when n = 3;

z2 = 12^1/4(cosπ+isinπ)

z2 = 12^1/4cis(π)

when n = 4;

z2 = 12^1/4(cos4π/3+isin4π/3)

z2 = 12^1/4cis(4π/3)

8 0
3 years ago
TEMA: Propriedade de Potência e Multiplicação de Números Negativos e Positivos.
GalinKa [24]
The correct answer is 34
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What is the answer and the work i have to do to get to it
harina [27]

Answer:

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Step-by-step explanation:

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