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2 years ago

What is the area of this figure? Enter your answer in the box. ___m²

Mathematics

1 answer:

ra1l [238]2 years ago

6 0

Well first you got figure out the formulas for the 2 triangles and the trapezoid.

The triangles formula for area is: A=b*h/2

The trapezoids formula for area is: A=1/2(b1+b2)*h

After you found the formulas you got to plug in the numbers.

For the first triangle it’s: A=9*5/2

The second triangle it’s: A=8*8/2

The trapezoid it’s: A=1/2(9+8)*5

After you plug in the numbers you have to solve the areas.

So the first triangle is: 9*5/2=9*5=45/2=22.5

So the area of the first triangle is 22.5

Then you have to solve the second triangle.

The second triangle: 8*8/2=8*8=64/2=32

So the area of the second triangle is 32

After solving the second triangle you have to solve the trapezoid.

Trapezoid: 1/2(9+8)*5=9+8=17=1/2(17)*5=17*5=85/2=
42.5

The area of the trapezoid is 42.5

After solving all of the shapes you have to add up all of the areas to get your full area.

22.5+32+42.5=22.5+42.5=65+32=97

So the area of the whole thing is 97

Hope this helps you!!!! Have a nice day!!!!

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Susan used 1/2 gallons of gas on Sunday and 3 5/8 gallons of gas on Monday. How many more gallons of gas did she use on Monday?

Nookie1986 [14]

Answer: 3 and 1/8 more

Step-by-step explanation:

You can start by converting to the same fraction and making the second one improper, so 29/8 and 4/8. Subtract them to find the difference and you are left with 25/8 or 3 1/8 gallons.

8 0

1 year ago

Consider the integral Integral from 0 to 1 e Superscript 6 x Baseline dx with nequals 25 . a. Find the trapezoid rule approximat

photoshop1234 [79]

Answer:

With n = 25, $\int_{0}^{1}e^{6 x}\ dx \approx 67.3930999748549$

With n = 50, $\int_{0}^{1}e^{6 x}\ dx \approx 67.1519320308594$

b. $\int_{0}^{1}e^{6 x}\ dx \approx 67.0715427161943$

The absolute error in the trapezoid rule is 0.08047

The absolute error in the Simpson's rule is 0.00008

Step-by-step explanation:

a. To approximate the integral $\int_{0}^{1}e^{6 x}\ dx$ using n = 25 with the trapezoid rule you must:

The trapezoidal rule states that

$\int_{a}^{b}f(x)dx\approx\frac{\Delta{x}}{2}\left(f(x_0)+2f(x_1)+2f(x_2)+...+2f(x_{n-1})+f(x_n)\right)$

where $\Delta{x}=\frac{b-a}{n}$

We have that a = 0, b = 1, n = 25.

Therefore,

$\Delta{x}=\frac{1-0}{25}=\frac{1}{25}$

We need to divide the interval [0,1] into n = 25 sub-intervals of length $\Delta{x}=\frac{1}{25}$ , with the following endpoints:

$a=0, \frac{1}{25}, \frac{2}{25},...,\frac{23}{25}, \frac{24}{25}, 1=b$

Now, we just evaluate the function at these endpoints:

$f\left(x_{0}\right)=f(a)=f\left(0\right)=1=1$

$2f\left(x_{1}\right)=2f\left(\frac{1}{25}\right)=2 e^{\frac{6}{25}}=2.54249830064281$

$2f\left(x_{2}\right)=2f\left(\frac{2}{25}\right)=2 e^{\frac{12}{25}}=3.23214880438579$

...

$2f\left(x_{24}\right)=2f\left(\frac{24}{25}\right)=2 e^{\frac{144}{25}}=634.696657835701$

$f\left(x_{25}\right)=f(b)=f\left(1\right)=e^{6}=403.428793492735$

Applying the trapezoid rule formula we get

$\int_{0}^{1}e^{6 x}\ dx \approx \frac{1}{50}(1+2.54249830064281+3.23214880438579+...+634.696657835701+403.428793492735)\approx 67.3930999748549$

To approximate the integral $\int_{0}^{1}e^{6 x}\ dx$ using n = 50 with the trapezoid rule you must:

We have that a = 0, b = 1, n = 50.

Therefore,

$\Delta{x}=\frac{1-0}{50}=\frac{1}{50}$

We need to divide the interval [0,1] into n = 50 sub-intervals of length $\Delta{x}=\frac{1}{50}$ , with the following endpoints:

$a=0, \frac{1}{50}, \frac{1}{25},...,\frac{24}{25}, \frac{49}{50}, 1=b$

Now, we just evaluate the function at these endpoints:

$f\left(x_{0}\right)=f(a)=f\left(0\right)=1=1$

$2f\left(x_{1}\right)=2f\left(\frac{1}{50}\right)=2 e^{\frac{3}{25}}=2.25499370315875$

$2f\left(x_{2}\right)=2f\left(\frac{1}{25}\right)=2 e^{\frac{6}{25}}=2.54249830064281$

...

$2f\left(x_{49}\right)=2f\left(\frac{49}{50}\right)=2 e^{\frac{147}{25}}=715.618483417705$

$f\left(x_{50}\right)=f(b)=f\left(1\right)=e^{6}=403.428793492735$

Applying the trapezoid rule formula we get

$\int_{0}^{1}e^{6 x}\ dx \approx \frac{1}{100}(1+2.25499370315875+2.54249830064281+...+715.618483417705+403.428793492735) \approx 67.1519320308594$

b. To approximate the integral $\int_{0}^{1}e^{6 x}\ dx$ using 2n with the Simpson's rule you must:

The Simpson's rule states that

$\int_{a}^{b}f(x)dx\approx \\\frac{\Delta{x}}{3}\left(f(x_0)+4f(x_1)+2f(x_2)+4f(x_3)+2f(x_4)+...+2f(x_{n-2})+4f(x_{n-1})+f(x_n)\right)$

where $\Delta{x}=\frac{b-a}{n}$

We have that a = 0, b = 1, n = 50

Therefore,

$\Delta{x}=\frac{1-0}{50}=\frac{1}{50}$

We need to divide the interval [0,1] into n = 50 sub-intervals of length $\Delta{x}=\frac{1}{50}$ , with the following endpoints:

$a=0, \frac{1}{50}, \frac{1}{25},...,\frac{24}{25}, \frac{49}{50}, 1=b$

Now, we just evaluate the function at these endpoints:

$f\left(x_{0}\right)=f(a)=f\left(0\right)=1=1$

$4f\left(x_{1}\right)=4f\left(\frac{1}{50}\right)=4 e^{\frac{3}{25}}=4.5099874063175$

$2f\left(x_{2}\right)=2f\left(\frac{1}{25}\right)=2 e^{\frac{6}{25}}=2.54249830064281$

...

$4f\left(x_{49}\right)=4f\left(\frac{49}{50}\right)=4 e^{\frac{147}{25}}=1431.23696683541$

$f\left(x_{50}\right)=f(b)=f\left(1\right)=e^{6}=403.428793492735$

Applying the Simpson's rule formula we get

$\int_{0}^{1}e^{6 x}\ dx \approx \frac{1}{150}(1+4.5099874063175+2.54249830064281+...+1431.23696683541+403.428793492735) \approx 67.0715427161943$

c. If B is our estimate of some quantity having an actual value of A, then the absolute error is given by $|A-B|$

The absolute error in the trapezoid rule is

The calculated value is

$\int _0^1e^{6\:x}\:dx=\frac{e^6-1}{6} \approx 67.0714655821225$

and our estimate is 67.1519320308594

Thus, the absolute error is given by

$|67.0714655821225-67.1519320308594|=0.08047$

The absolute error in the Simpson's rule is

$|67.0714655821225-67.0715427161943|=0.00008$

6 0

2 years ago

Matt walker is paid weekly and earns 3.5% straight commission on sales of $6,500 or less and 5% on sales in excess of $6500.last

Nina [5.8K]

His total sales were "x"

now, we know that 3.5% of "x" plus 5% of "x", will add up to his total commission, including sales of 6500 or less or more

so the commission for 6500 or less, is 3.5% of "x" or (3.5/100)*x -> 0.035x
the commission for above 6500 is 5% or (5/100) * x --> 0.05x

we know, that both commissions added together, are $415

thus

0.035x + 0.05x = 415 <----- solve for "x"

4 0

2 years ago

What is the solution for the equation 6x − 8 = 4x?

ira [324]

Answer:

Step-by-step explanation:

First, get x to one side.

subtract 6x to both sides

-8 = -2x

Then divide -2 to both side

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3 years ago

What is the simplified version of the expression [(5-1)^2+3^2]/(30 / 6)

VARVARA [1.3K]

Answer:

Exact form is $\frac{16}{5} +\frac{3^2}{5}$

the decimal form is 5

Step-by-step explanation:

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2 years ago