Let the function f be defined as f(x)= 5x^2 - 7(4x+3). What is the value of f(3)
1 answer:
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Answer:
: p= .78
: p > .78
Step-by-step explanation:
Determining the null and alternate hypotheses of a scenario require several components. The first is if one should use p or mu. This depends on if they are assessing a proportion or a mean, since the publisher states a percentage, you know that they are asking for a proportion, and therefore should use p. Next, they will need to assess what value to use for the hypothesis statements, here only .78 is provided and therefore should be used in both. Finally, it is time to add in the comparison symbols, the null hypothesis always uses an equals sign so it therefore becomes:
: p= .78
The alternate hypothesis then needs to consider if the researchers claim that the new proportion is greater, fewer, or different. In this case it is greater as they think that the ownership is above 78%, so a greater than sign would be used and the final statement would be:
: p > .78
Yes it does include the test point (0, 0)
- equation: y > -3x -5
- y > -3(0) -5
- y > -5
- y > -3x -5
<u>switch sides</u>
- -3x - 5 < 0
- -3x < 5
<u>Multiply both sides by -1 reverses the inequality</u>
- x > -5/3
Thus, the following (0, 0) comes under the following x > -5/3 and y > -5
Answer: hello your question was poorly written but i was able to the get missing parts online which enabled me resolve your question
answer:
a) a = 0.1096
b) 1.89 watts
Step-by-step explanation:
Std of output voltage = 0.25 volt
H0 : μ = 5 volts
Ha : μ ≠ 5 volts
n = 16
a) Acceptance region = 4.9 ≤ X ≤ 5.1
Determine the value of a
value of a = 0.0548 + 0.0548
= 0.1096
<em>attached below is the reaming solution</em>
note : a is a type 1 error
b) power of test
True mean output voltage = 5.1 volts
P = - 1.89 watts
power cant be negative hence the power of the test = 1.89 watts
