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frozen [14]
3 years ago
5

PLEASE ANSWER

Mathematics
2 answers:
Gekata [30.6K]3 years ago
8 0

Answer:

The answer is C I believe

Step-by-step explanation:

Sidana [21]3 years ago
7 0
C. d=0.36 it’s very simples.
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Complete the square to determine the minimum or maximum value of the function defined by the expression.
FrozenT [24]

Answer:

Option D. minimum value at −38

Step-by-step explanation:

we have

x^{2}-12x-2

Let

y=x^{2}-12x-2

Complete the square

y+2=x^{2}-12x

y+2+36=(x^{2}-12x+36)

y+38=(x^{2}-12x+36)

y+38=(x-6)^{2}

y=(x-6)^{2}-38 ------> equation of a vertical parabola in vertex form

The vertex is the point (6,-38)

The parabola open upward-----> the vertex is a minimum

therefore

minimum value at −38

3 0
3 years ago
An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y
aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                               P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average time = 23.92 minutes

             s = sample standard deviation = 6.72 minutes

             n = sample of times = 40

             \mu = population mean assembly time

<em> Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

<u>So, a 98% confidence interval for the population mean, </u>\mu<u> is; </u>

P(-2.426 < t_3_9 < 2.426) = 0.98  {As the critical value of z at 1%  level

                                               of significance are -2.426 & 2.426}  

P(-2.426 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.426) = 0.98

P( -2.426 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

P( \bar X-2.426 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

<u>98% confidence interval for</u> \mu = [ \bar X-2.426 \times {\frac{s}{\sqrt{n} } } , \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ]

                                     = [ 23.92-2.426 \times {\frac{6.72}{\sqrt{40} } } , 23.92+2.426 \times {\frac{6.72}{\sqrt{40} } } ]  

                                    = [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0
2 years ago
In a history class, students take a weekly multiple choice quiz consisting of 6 questions, each with 4 possible answers. if a st
Mademuasel [1]
There are 24 possible answers, 6 are correct answers and 18 are incorrect answers. By use of the hypergeometric distribution the probabilities of each possible number of randomly selected correct answers can be found, as follows:
P(0) = 0.1379, P(1) = 0.3819, P(2) = 0.341, P(3) = 0.1213, P(4) = 0.017, P(5) = 0.0008, P(6) = 0.000007.
The expected or mean number of correct answers is found from:
E(X)=0\times0.1379+1\times0.3819+2\times0.341+3\times0.1213+4\times0.017+5\times0.0008+6\times0.000007=1.4998
The answer is: 1.4998

8 0
3 years ago
Simplify 8(x-3)-4(2x-7)
Paraphin [41]

Answer:

Your solution is 4.

Step-by-step explanation:

4 0
3 years ago
Explain how to calculate the surface area of a composite figure in your own words.
AleksAgata [21]
To calculate the <span>surface area of a composite figure you must apply the formulas for calculate the area of each figure that is part of the composite figure and then, you must sum all the areas calculated.

 For example, is the composite figure is form by a triangle and rectangle, the surface area of the composite figure will be:

 SA= Area of the triangle+ Area of the rectangle= (bh/2)+bh</span>
8 0
3 years ago
Read 2 more answers
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