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mestny [16]
4 years ago
14

If the first-order angle is 22.0, what can be said about the third-order angle? a. It must be within one degree of 75 b. It depe

nds on the light wavelength, the distance of the screen from the grating, and the line spacing in the grating. c. It does't exist.
Physics
1 answer:
Hatshy [7]4 years ago
8 0

Answer:

It depends on the light wavelength, the distance of the screen from the grating, and the line spacing in the grating.

(b) is correct option

Explanation:

Given that,

Order number = 1

Angle = 22.0°

We need to calculate the third-order angle

Using formula of distance

d\sin\theta=n\lambda

For first order,

\sin\theta_{1}=\dfrac{n\lambda}{d}

\theta_{1}=\sin^{-1}\dfrac{1\lambda}{d}

Where, d = the distance of the screen from the grating

n = order number

\lambda=wavelength

For second order,

\theta_{2}=\sin^{-1}\dfrac{2\lambda}{d}

For third order,

\theta_{3}=\sin^{-1}\dfrac{3\lambda}{d}

So, It depends on the light wavelength, the distance of the screen from the grating, and the line spacing in the grating.

Hence, This is the required solution.

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You fire a projectile 35° above horizontal with an initial velocity of 200m/s. It lands in a valley 300m below the launch point.
Brilliant_brown [7]

Answer:

See below

Explanation:

Vertical component of initial velocity  =  200 sin 35° = 114.72 m/s

then use position formula      a = 9.81 m/s^2

  0  = 300 + 114.72 t  -  1/2 (9.81)(t^2)

            use quadratic formula with a = - 4.905    b = 114.72   c = 300

              to find t = <u>25.76 seconds </u>

<u />

To find the range

   ( horizontal distance the projectile lands from launch point)

Horizontal component of initial velocity    200 cos 35 = 163.83 m/s

 ( it flies horizontally at this speed for  <u>25.76 seconds <==found above</u>)

    163.83  m/s  *  25.76 s = <u>4220.3 meters</u>

3 0
2 years ago
A vehicle moving along at 5m/s. What should be the constant deceleration in order to stop it within 15m?​
Oduvanchick [21]

Answer:

a = -5/6 m/s²

Explanation:

v² = u² + 2as

a = (v² - u²) / 2s

a = (0² - 5²) / 2(15)

a = -5/6 m/s²

This assumes the initial velocity was in the positive direction.

5 0
3 years ago
A baseball is thrown 50.0m in 3.0s, what is the average speed of the baseball? Calculated answer is 16.666667! What is the corre
castortr0y [4]

Answer:

20m/s

Explanation:

Given parameters:

Distance of throw = 50m

Time  = 3s

Unknown:

Average speed  = ?

Solution:

Average speed is distance divided by time;

  Average speed  = \frac{distance }{time}

Insert the parameters and solve;

  Average speed  = \frac{50}{3}   = 16.66667m/s  = 20m/s

5 0
3 years ago
In a 4.0-kilometer race, a runner completes the first kilometer in 5.9 minutes, the second kilometer in 6.2 minutes, the third k
Svetlanka [38]

As per the question the total distance is given as 4 km.

We are asked to calculate the average speed.

The time taken by the body to travel each kilometre are 5.9 min,6.2 min.,6.3min. and 6 min. respectively.

The average speed of a body is defined as the ratio of total distance travelled by the body to the total time.

Mathematically the average speed is written as _

V= Total distance/Total time

i.e V = S/T

Where S is the total distance travelled and T is the total time

Here total distance (S)= 4 km

The total time T= (5.9+6.2 +6.3+ 6.0 )minutes

=24.4 min.

Hence average speed V = 4 km/24.4 min

= 0.16 km/min.

Hence the correct option is A .


3 0
3 years ago
An apple falls out of a tree from a height of 2.3 m What is the impact speed of the apple?
ivann1987 [24]

Answer:

6.72 m/s

Explanation:

recall that the equations of motion may be expressed as

v² = u² + 2as

where,

v = final velocity,

u = initial velocity = 0 m/s because it is stationary before it starts falling

a = acceleration (in this case because it is falling, it is the acceleration due to gravity = 9.81 m/s²)

s = distance traveled = 2.3m

in our case, if we neglect air resistance, then we simply substitute the known values above into the equation of motion.

v² = u² + 2as

v² = 0² + 2(9.81)(2.3)

v² = 45.126

v = √45.126

v = 6.72 m/s

6 0
4 years ago
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