Question

Solve x^2 - 6x = -5 by completing the square.

Answer 1

$x^2-6x=-5\\\\x^2-2x\cdot3=-5\ \ \ |+3^2\\\\\underbrace{x^2-2x\cdot3+3^2}_{(a-b)^2=a^2-2ab+b^2}=-5+3^2\\\\(x-3)^2=-5+9\\\\(x-3)^2=4\to x-3=\pm\sqrt4\\\\x-3=-2\ \vee\ x-3=2\ \ \ |+3\\\\x=1\ \vee\ x=5$