In point slope form, the equation is y-7=(-10/3)(x+9). In slope-intercept form, it is y=(-10/3)x-23.
First find the slope of the line. The formula for slope is
m=(y₂-y₁)/(x₂-x₁)
Using our points, we have
m=(-3-7)/(-6--9) = -10/3
Plug this into point slope form:
y-y₁=m(x-x₁)
y-7=(-10/3)(x--9)
y-7=(-10/3)(x+9)
Using the distributive property:
y-7=(-10/3)*x+(-10/3)*9
y-7=(-10/3)x-90/3
y-7=(-10/3)x-30
Add 7 to both sides:
y=(-10/3)x-23
Answer:
I think
A display order of numbers are called <u>sequences</u>.
The picture is not there what is the question
Answer:
50⁰
Step-by-step explanation:
Since j and k are parallel lines cut by two transversals,
2+3+5=180⁰ <em>(</em><em>Allied</em><em> </em><em>angles</em><em>)</em>
We are given 2(60⁰) and 5(70⁰)
so,
60⁰+3+70⁰=180⁰
60+70=130
130⁰+3=180⁰
Bring the 130⁰ to the R.H.S
3=180⁰-130⁰
Therefore,
3=50⁰
Basically all you have to do is plug in numbers for Y and C. the formula is (y,x) so use numbers like (1,3) and as long as it fits in the equation (the equation ends up true. like in this case (1 < 2) which means it worked) you can graph that point.
