Answer:
12,9
Step-by-step explanation:
52m(-872)=92.28763m
The method would be the power of m with 92=92.28763
Create a system if equations to solve this.
First equation:
25m + 24e = 220
Second equation:
m + e = 9
Then you must solve the second equation for a variable.
Change m + e = 9 to e = 9 - m.
Then substitute (9 - m) for e in the first equation.
So 25m +24e = 220 becomes 25m + 24(9 - m) = 220.
Now you can solve the first equation because the only variable in it is m.
25m + 24(9 - m) = 220 (Original equation)
25m + 216 - 24m = 220 (Distribute)
m + 216 = 220 (Combine like terms)
m = 4 (Simplify)
Now plug in 4 for m in the second equation.
m + e = 9 (Original equation)
(4) + e = 9 (Substitute)
e = 5 (Simplify)
m represents Math Books and e represents English Books, so Nicole purchased 4 Math Books and 5 English Books.
X + 5y = 6
5y = -x + 6
y = -1/5x + 6/5....the slope here is -1/5. A perpendicular line will have a negative reciprocal slope. All that means is flip the original slope and change the sign. So we flip -1/5 and make is -5/1....and we change the sign...making it 5/1 or just 5. So our perpendicular line will have a slope of 5.
y = mx + b
slope(m) = 5
(2,-2)...x = 2 and y = -2
sub and find b, the y int
-2 = 5(2) + b
-2 = 10 + b
-2 - 10 = b
-12 = b
so ur perpendicular equation is : y = 5x - 12 <=
Answer:
<u><em>(-1,1)</em></u>
Step-by-step explanation:
We can solve this by either graphing and finding ther point the lines intersect, or mathematically, I'll do both.
<u>Graphing:</u>
<u>Mathematically:</u>
−2x + 4y = 6
y = 2x + 3
See the attached graph. The lines intersect at (-1,1)
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I'll rearrange the first equation (to make it easier for me):
−2x + 4y = 6
4y = 2x + 6
y = (1/2)x + 1.5
Now lets substitute the second equation into the first so that we can eliminate y:
y = 2x + 3
[(1/2)x + 1.5] = 2x + 3
- (3/2)x = (3/2)
x = -1
If x = -1:
y = 2(-1) + 3
y = 1
The solution is x = -1 and y = 1, or (-1,1)
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Both approaches give us (-1,1), the solution to the system of equations. It is the only point that satisfies both equations.
