2. Janice and Jasmine were each given a piece of ribbon of equal length. Janice cuts her ribbons into equal lengths of 2 m, whil
e Jasmine cuts her ribbons into equal lengths of 5 m. If there was no remainder in both cases, find the shortest possible length of ribbon given to them.
Since there is no remainder we simply need to find the least common multiple of each of the lengths of Janice and Jasmin's strings until we find a multiple that matches for each. Like so...
2*1 = 2 5*1 = 5
2*2 = 4 5*2 = 10
2*3 = 6
2*4 = 8
2*5 = 10
Finally, we have found the first common multiple which is 10m. That means that the shortest equal length for both Janice's and Jasmin's ribbon is 10m.
Step-by-step explanation:12x12 =144 and 7x7= 49 subtract 144-49 and get 95 the square root of 95 is approximately 9.747 rounded to the nearest hundredths place is 9.75
