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4 years ago

PLEASE HURRY!!!

Mathematics

1 answer:

RoseWind [281]4 years ago

4 0

terms is x first then terms in y and constant after the equals

Its C

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aleksandr82 [10.1K]

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5 0

3 years ago

Read 2 more answers

If y varies inversely as the square of x, and y= 1/8 when x=1, find y when x=5

Nata [24]

y = k / x² ( y varies inversely as the square of x )

y = 1/8 when x = 1:

1/8 = k / 1²

8 k = 1

k = 1/8

For x = 5:

y = 1/8 / 5² = 1/8 : 25 = 1/8 · 1/25 = 1/200

Answer: A ) 1/200

Hope This Helps!!!

5 0

3 years ago

Read 2 more answers

Hurry in need of help! Please

Bas_tet [7]

$\\ \sf\dashrightarrow \dfrac{x+20}{2}=3x$

$\\ \sf\dashrightarrow x+20=2(3x)$

$\\ \sf\dashrightarrow x+20=6x$

$\\ \sf\dashrightarrow 20=6x-x$

$\\ \sf\dashrightarrow 5x=20$

$\\ \sf\dashrightarrow x=\dfrac{20}{5}$

$\\ \sf\dashrightarrow x=4$

3 0

3 years ago

Can someone help me please

Misha Larkins [42]

Answer:

x= 13, angle 1= 37, and angle 2= 53

Step-by-step explanation:

So you have 2x+11+1+4x=90 degrees

If you simplify it, it becomes 6x+12=90 degrees

Then, you rearrange; 6x=90-12 or 6x= 78

So then, x=13

For angle 1 its 2x+11= 37 degrees

And angle 2 is 1+4x= 53 degrees

7 0

4 years ago

Since the area under the normal curve within two standard deviations of the mean is 0.95, the area under the normal curve that c

alukav5142 [94]

Answer:

$X \sim N (\mu ,\sigma)$

And for this case we know this condition:

$P(\mu-2\sigma$

By the complement rule we know that:

$P(X< \mu -2\sigma \cup X>\mu +2\sigma) = 1-0.95=0.05$

But since the distribution is symmetrical we know that:

$P(X\mu +2\sigma) = 0.025$

So then the statement for this case is FALSE.

b. False

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

For this case if we define the random variable of interest X and we know that this random variable follows a normal distribution:

$X \sim N (\mu ,\sigma)$

And for this case we know this condition:

$P(\mu-2\sigma$

By the complement rule we know that:

$P(X< \mu -2\sigma \cup X>\mu +2\sigma) = 1-0.95=0.05$

But since the distribution is symmetrical we know that:

$P(X\mu +2\sigma) = 0.025$

So then the statement for this case is FALSE.

b. False

5 0

4 years ago