9514 1404 393
Answer:
see attached
Step-by-step explanation:
The first attachment shows the rectangles with the area inside and the width on the right. The synthetic division of area by width gives the polynomial coefficients for length. The lengths are marked above the rectangles. The synthetic division is shown the 2nd and 3rd attachments.
Answer:
6
Step-by-step explanation:
Answer:
∠B ≅ ∠F ⇒ proved down
Step-by-step explanation:
<em>In the </em><em>two right triangles</em><em>, if the </em><em>hypotenuse and leg</em><em> of the </em><em>1st right Δ ≅</em><em> the </em><em>hypotenuse and leg</em><em> of the </em><em>2nd right Δ</em><em>, then the </em><em>two triangles are congruent</em>
Let us use this fact to solve the question
→ In Δs BCD and FED
∵ ∠C and ∠E are right angles
∴ Δs BCD and FED are right triangles ⇒ (1)
∵ D is the mid-point of CE
→ That means point D divides CE into 2 equal parts CD and ED
∴ CD = ED ⇒ (2) legs
∵ BD and DF are the opposite sides to the right angles
∴ BD and DF are the hypotenuses of the triangles
∵ BD ≅ FD ⇒ (3) hypotenuses
→ From (1), (2), (3), and the fact above
∴ Δ BCD ≅ ΔFED ⇒ by HL postulate of congruency
→ As a result of congruency
∴ BC ≅ FE
∴ ∠BDC ≅ ∠FDE
∴ ∠B ≅ ∠F ⇒ proved
stranger things A jewellery shop is having a sale.
A bracelet is reduced to £240.
a) What is the original price?
A ring is reduced to £840.
This is 40% of the original price.
b) Work out the original price of this ring.A jewellery shop is having a sale.
A bracelet is reduced to £240.
a) What is the original price?
% of the original price.
b) Work out the original price of this ring.A jewellery shop is having a sale.
A bracelet is reduced to £240.
a) What is the original price?
A ring is reduced to £840.
This is 40% of the original price.
b) Work out the original price of this ring.A jewellery shop is having a sale.
A brace
A ring is reduced to £840.
This is 40% of the original price.
b) Work out the original price of this ring. yeey this is important
Answer:
Quad 1
Step-by-step explanation:
AXYZ is in the 2nd quad bc of the rotation, then goes back to 1st quad bc of reflection (y axis). After this, the translation doesn't affect the movement of quadrants. A""X""Y""Z"' lands in quadrant 1.
