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3 years ago

5

There are 8 girls and 5. boys on the math team which ratio correctly describes the relationship between boys and girls on the ma

th team

1 answer:

Elena-2011 [213]3 years ago

6 0

Answer:

8:5

Step-by-step explanation:

I'm honestly not sure how to explain this because it's just a ratio, but good luck!

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In the inequality 6a+4b>10, what could be the possible value of a if b=2?

Arlecino [84]

We are given the following inequality:

$6a+4b>10$

If we replace b = 2, we get:

$\begin{gathered} 6a+4(2)>10 \\ 6a+8>10 \end{gathered}$

Now we solve for "a" first by subtracting 8 on both sides:

$\begin{gathered} 6a+8-8>10-8 \\ 6a>2 \end{gathered}$

Now we divide both sides by 6

$\frac{6a}{6}>\frac{2}{6}$

Simplifying:

$a>\frac{1}{3}$

Therefore, for b = 2, the possible values of "a" are those that are greater than 1/3

3 0

2 years ago

Q3. Kylie sits two maths test. She scores 19/25 in the first one, and 16/20 in the second one.

Rina8888 [55]

She done better at the 2nd test because she only got 4 wrong but on the first test she got 6 wrong.

7 0

3 years ago

Read 2 more answers

ΔXYZ ≅ΔFED where m∠X = 50°, m∠Y=30°, m∠D=2y+10, XY =9 and EF=3x−12. Solve for x and y.

Delicious77 [7]

Answer:

The value of x is 7 and value of y is 45

Step-by-step explanation:

In ΔXYZ

∠X = 50°, ∠Y=30°

To Find ∠Z we will use angle sum property of triangle (Sum of all angles of triangles is 180°)

So,∠X + ∠Y + ∠Z = 180°

So,50°+30°+ ∠Z = 180°

∠Z=180°-80°

∠Z=100°

Now we are given that ΔXYZ ≅ΔFED

So, the corresponding sides are equal and the corresponding angles are equal.

So, ∠Z= ∠D

So, 100=2y+10

100-10=2y

90=2y

45=y

Now XY = EF

So, 9 = 3x-12

21=3x

7=x

Hence The value of x is 7 and value of y is 45

5 0

3 years ago

Horatio wants to ship a batch of 8 machine parts. The packaging for each part weighs 2 pounds. If each part weighs x pounds, whi

Sever21 [200]

Here is what we know:
8 machine parts
each part = x pouunds
packaging for each part is 2 pounds so 16 pounds for packaging

If y=total weight wiith that information we can form this equation
y=8x + 16

If each part equals 6 pounds the total shipment will be
y=8x+16
y=8(6) + 16
y= 48 + 16
y=64

5 0

3 years ago

Read 2 more answers

a student takes two subjects A and B. Know that the probability of passing subjects A and B is 0.8 and 0.7 respectively. If you

aniked [119]

Answer:

0.64 = 64% probability that the student passes both subjects.

0.86 = 86% probability that the student passes at least one of the two subjects

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Passing subject A

Event B: Passing subject B

The probability of passing subject A is 0.8.

This means that $P(A) = 0.8$

If you have passed subject A, the probability of passing subject B is 0.8.

This means that $P(B|A) = 0.8$

Find the probability that the student passes both subjects?

This is $P(A \cap B)$ . So

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

$P(A \cap B) = P(B|A)P(A) = 0.8*0.8 = 0.64$

0.64 = 64% probability that the student passes both subjects.

Find the probability that the student passes at least one of the two subjects

This is:

$p = P(A) + P(B) - P(A \cap B)$

Considering $P(B) = 0.7$ , we have that:

$p = P(A) + P(B) - P(A \cap B) = 0.8 + 0.7 - 0.64 = 0.86$

0.86 = 86% probability that the student passes at least one of the two subjects

3 0

3 years ago