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Greeley [361]
3 years ago
6

How do u factor out the coefficient of the variable??? -6z + 12 equals what

Mathematics
1 answer:
Bezzdna [24]3 years ago
7 0
-6z+ 12
= -6(z -2) (distributive property)

The final answer is -6(z -2)~

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DaMarcus says the number 24/6 belongs only to the set of rational numbers. Explain his error
malfutka [58]
24/6 is equal to 4 so it is an interger and a whole number too because 24 ÷ 6 = 4.
6 0
3 years ago
I need help and can you plz tell me the answer
Sav [38]
The least common multiple of 4 and 7 is 28 I think sorry I haven't been in school for a week
7 0
3 years ago
What is the solution to the system of equations below? x 3 y = 15 and 4 x 2 y = 30 (6, 3) (3, 6) (7, –6) (–6, 7).
swat32

Answer: (6 , 3)

Step-by-step explanation: Given

x + 3y =15 ------- equation 1

4x + 2y = 30 --------- equation 2

x = 15 - 3y

Put value of x in equation 2

4 (15 - 3y) + 2y = 30

60 - 12y + 2y = 30

-10y = -30

divide by '-10' on both sides

y = 3

now, put value of y in equation 1

x + 3(3) = 15

x + 9 = 15

x = 15 - 9

x =  6

So , (x , y) = (6 , 3)

7 0
2 years ago
1/3 of 12 = 2/3 of<br><br> 1/3 of 12 is the same as 2/3 of
julsineya [31]

Answer:

6

Step-by-step explanation:

since;

1/3 of 12 = 4

so,

(2/3) of x = 4

x=4(3/2)= 6

5 0
3 years ago
When the expression $-2x^2-20x-53$ is written in the form $a(x+d)^2+e$, where $a$, $d$, and $e$ are constants, then what is the
Sladkaya [172]
We start with 2 x^{2} -20x-53 and wish to write it as a(x+d) ^{2} +e

First, pull 2 out from the first two terms: 2( x^{2} -10x)-53

Let’s look at what is in parenthesis. In the final form this needs to be a perfect square. Right now we have x^{2} -10x and we can obtain -10x by adding -5x and -5x. That is, we can build the following perfect square: x^{2} -10x+25=(x-5) ^{2}

The “problem” with what we just did is that we added to what was given. Let’s put the expression together. We have 2( x-5) ^{2}-53 and when we multiply that out it does not give us what we started with. It gives us 2 x^{2} -20x+50-53=2 x^{2} -20x-3

So you see our expression is not right. It should have a -53 but instead has a -3. So to correct it we need to subtract another 50.

We do this as follows: 2(x-5) ^{2}-53-50 which gives us the final expression we seek:

2(x-5) ^{2}-103

If you multiply this out you will get the exact expression we were given. This means that:
a = 2
d = -5
e =  -103

We are asked for the sum of a, d and e which is 2 + (-5) + (-103) = -106


7 0
3 years ago
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