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Mashutka [201]
3 years ago
6

A car purchased for $15,000 depreciates under a straight-line method in the amount of $950 each year. Which equation below best

models this depreciation?
Mathematics
2 answers:
alexandr1967 [171]3 years ago
8 0
I believe it will be B. y = 15,000 - 950 x
So after a year it will be 15,000 - 950 = 14,050
Tems11 [23]3 years ago
6 0

Answer: y = 15,00 - 950x

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Alexeev081 [22]

Answer:

<h2>         a ∈ (-∞, -3></h2>

Step-by-step explanation:

<h3>- 21 ≥ 3(a - 7) + 9</h3><h3>- 21 ≥ 3a - 21 + 9</h3>

  +21         +21

<h3>    0 ≥ 3a + 9 </h3><h3>3a + 9 ≤ 0</h3>

      -9      -9

<h3>3a ≤ - 9</h3>

 ÷3    ÷3

<h3>  a ≤ -3 </h3><h3>a ∈ (-∞, -3></h3>
8 0
3 years ago
I need help!!!!please someone tell me the answer!!!!
Alexeev081 [22]

Answer:

c: v=5000(1.35)

Step-by-step explanation:

3.5 interest in point-slope decimal form is 1.35.

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3 0
3 years ago
Write the equation that passes through the following points:<br><br> (5,0) and (−10,−5)
Vikentia [17]

Answer:

The answer is:

y =  \frac{1}{3} x -  \frac{5}{3}

Step-by-step explanation:

❃Incase you forgot what the linear equation formula is ☟

y = mx + b

❃Incase you also forgot, The is what the slope formula is ☟

m = \frac{y_2 - y_1 }{x_2 - x_1}

➊ First: We are going to be solving for the slope.

m = \frac{  - 5 - 0}{ - 10 - 5} = \frac{ - 5}{  - 15} =  \frac{1}{3}

➋Second: We find the y-intercept.

y = mx + b \\ 0 =  \frac{1}{3} (5) + b \\ 0 =  \frac{5}{3}  + b \\ \frac{  -   \frac{5}{3}  =  -  \frac{5}{3 }   \:  \:  \:  \:  \:  \:  \: \: \: \: \: \: }{  -  \frac{5}{3}  = b}

➌Third: Plug in.

y =  \frac{1}{3} x -  \frac{5}{3}

4 0
2 years ago
What is the slope <br> (-3,1) (4,5)
myrzilka [38]
The slope in short is:
4/7
7 0
2 years ago
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If a =7 and b = 2 what is 2ab
e-lub [12.9K]

Answer:

28

Step-by-step explanation:

2(7)(2) =28

5 0
2 years ago
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