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3 years ago

Someone please help me with this. thanks. and please explain.

Mathematics

2 answers:

dezoksy [38]3 years ago

6 0

Answer:

The cities are actually 190 km apart.

Step-by-step explanation:

Consider the provided information.

It is given that a map scale is 1 cm : 50 km.

We need to find the distance between the two cities if they are 3.8 cm apart.

To find the actual distance between the two cities using the map, multiply each side of the relationship by 3.8

3.8 × 1 cm : 3.8 × 50 km

3.8 cm : 190 km

The cities are actually 190 km apart.

just olya [345]3 years ago

4 0

It would be 190 km because you do 5 x 3 to get 15 add a 0 at the end of it. Than at 40 because .8 of 150 is 40. Then 150+40= 190

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Do i pee or poop before my test, (i can only do one). :(

Oksana_A [137]

Answer:

Poop

Step-by-step explanation:

People might not be able to see the poop through your pants, but pee will be very noticeable.

4 0

2 years ago

Read 2 more answers

Two factory plants are making TV panels. Yesterday, Plant A produced 16,000 panels. Five percent of the panels from Plant A and

weeeeeb [17]

Answer:

Number of panels produced by Plant B is 8,000.

Step-by-step explanation:

The number of panels produced by Plant A = 16,000

The number of defective panels from A = 5%

Now, 5% of 16,000 = $\frac{5}{100} \times 16,000 = 800$

So, out of 16,000 panels produced by pant A , 800 are defective. .. (1)

Let us assume number of panels produced by Plant B = m

The number of defective panels from B = 2%

Now, 2% of m = $\frac{2}{100} \times m = 0.02 m$

So, out of total m panels produced by pant B , 0.02 m are defective. .. (2)

Now, total panels produced over all = Panels by A + Panels by B

= 16,000 + m

The percentage of defected panels over all = 4%

Now, 4% of (16,000 + m) = $\frac{4}{100} \times (16,000+m) = (0.04)(16,000 + m)$

Also, the total number of defective panels = Defective from A + Defective from B

⇒(0.04)(16,000 + m) = 800 + 0.02 m from (1) and (2)

or, 640 + 0.04 m = 800 + 0.02

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5 0

3 years ago

Find the compound interest on Rs. 2000 for one year at the rate of '20%' per annum. If theinterest compounded quarterly.

trasher [3.6K]

Given:

Principal = Rs. 2000

Rate of interest = 20% p.a. compounded quarterly.

Time = 1 year

To find:

The compound interest.

Solution:

Formula for amount:

$A=P\left (1+\dfrac{r}{n}\right)^{nt}$

where,

P = Principal

r = Rate of interest

t= Time

n = number of times interest compounded in an year.

Putting P=2000, r=0.2, n=4 and t=1, we get

$A=2000\left (1+\dfrac{0.2}{4}\right)^{4(1)}$

$A=2000\left (1.05\right)^{4}$

$A=2000\left (1.21550625\right)$

$A=2431.0125$

Now, the compound interest is

$C.I.=A-P$

$C.I.=2431.0125-2000$

$C.I.=431.0125$

Therefore, the compound interest is Rs 431.0125.

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2 years ago

The function ƒ(x) = x−−√3 is translated 3 units in the negative y-direction and 8 units in the negative x- direction. Select the

fenix001 [56]

Answer:

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$f(x+8)=\sqrt[3]{(x+8)} -3$

----------------------------

Hope it helps..

Have a great day!!

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2 years ago

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Free_Kalibri [48]

Answer:

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Step-by-step explanation:

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3 years ago