All categories

3 years ago

How do u guys solve this problem

Mathematics

2 answers:

vodka [1.7K]3 years ago

8 0

Set 19x+3 equal to 21x-3 as they are of equal measures. They are corresponding angles

PolarNik [594]3 years ago

3 0

Those two angles are congruent(corresponding), so we can set these equal to each other.
19x+3=21x-3
-2x=-6
x=3

You might be interested in

The diagram represents the factorization of a2 + 8a + 12.What is the missing number that will complete the factorization? a2 + 8

jarptica [38.1K]

To factor a quadratic of the form ax^2+bx+c you need to find two values, j and k, which satisfy two conditions...

jk=ac=12 and j+k=b=8, so j and k must be 2 and 6

Then the factors are just (a+j)(a+k), in this case:

(a+2)(a+6)

So the missing term was 6

8 0

3 years ago

Read 2 more answers

Q.4 - Please Help, I will give Brainliest!!!!

ankoles [38]

-x/12 = -(1/12)(x) or D

4 0

3 years ago

Solve the equations 4× + 4 = 20. Write the problem on the sketch pad then solve the problem algebraically. I need shown work.

tensa zangetsu [6.8K]

Answer:

x = 4

Step-by-step explanation:

I don't know what you mean by sketch pad but here is the working out

4x + 4 = 20

-4 -4

4x = 16

÷4 ÷4

x = 4

Hope this helps :)

4 0

3 years ago

“Half of a number (n) is at least 22."<br> translate and solve

viktelen [127]

Answer:

n >_44

Step-by-step explanation:

1/2n>_22

(times 2 on both sides)

n >_44

*** >_ is greater than or equal to sign

8 0

3 years ago

The population of a town increases at a rate of 5% every year. The population of this town was 10,400 in 2017. What will the pop

galben [10]

Answer:

The population of the town in 2020 will approx. be 12,039.

Step-by-step explanation:

The initial population in the year 2017 = 10,400

Increase in population every yea r = 5%

Now, 5% of 10, 400 = $\frac{5}{100} \times 10, 400 = 520$

Hence, the population in the year 2018 = 10,400 + 520 = 10,920

Now, in the year 2019

5% of 10, 920 = $\frac{5}{100} \times 10, 920 = 546$

Hence, the population in the year 2019 = 10,920 + 546 = 11,466

Now, in the year 2020

5% of 11,466 = $\frac{5}{100} \times 11,466 = 573.3$

or, the population in the year 2020 = 11,466 + 573.3 = 12,039.3

The population of the town in 2020 will approx. be 12,039.

6 0

3 years ago