Answer:
I do believe its 5 units, if I am incorrect I apologize
Step-by-step explanation:
Find out how much over the 10 years whatever it says and then use that to explain if it's worth is
Answer:
A) THE MEAN DIFFERENCE = 22.2 - 20 = 2.2
B) HERE WE NEED TO CALCULATE THE MARGIN OF ERROR
AS GIVEN THE VARIANCE = 384
THEREFORE STANDARD DEVIATION = (384)^(1/2) = 19.59
THE MARGIN OF ERROR = STANDARD DEVIATION / SQRT(N) = 19.59/SQRT(25) = 19.59/5 = 3.91
C) AS THE SAMPLE SIZE IS LESS THEN 30 THEREFORE WE WILL DO IT BY THE T TEST
We need to test the null H0 : µ = 20 against the TWO-sided alternative H1 : µ\neq 20, at level α = 0.05. Since n is SMALL, we will do a SMALL-sample T-test. The rejection region is T >Tα = 1.96OR T<-Tα = -1.96, using the normal table.
T= (X − µ0) /(S/√ n) = (22.2 − 20)/( 19.59/ √ 25) = 0.56 Since T = 0.56 < 1.96, H0 is ACCEPTED. Thus, there is significant evidence at 5% signifi- cance level .
Step-by-step explanation:
