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Nataly [62]
4 years ago
13

A map uses a scale of 1 in. : 25 mi. If the distance between two cities on the map is 3.5 inches, what is the actual distance be

tween the two cities?
A. 0.21
B. 11.4
C. 2,917
D. 6,563
Mathematics
1 answer:
Aleonysh [2.5K]4 years ago
5 0

its c because its c and it show can be c

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PLS!! help just answer no download or links
mariarad [96]

Answer:

6.15 in squared

Step-by-step explanation:

Hope This Helps :b

3 0
3 years ago
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Is (2,5) a solution of y=3x-10?
Lynna [10]
To see if (2,5) is a solution of the line y = 3x - 10, you need to plug in the coordinate values for x and y. This gets you 5 = 3(2) - 10. Evaluating the right side gives 5 ≠ -4, which is not a true statement. This means that the answer to your problem is no, (2,5) is not a solution of y = 3x - 10. Hope this helps and have a nice day!
3 0
3 years ago
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A equation of a line in slope intercept form with the given slope and Y-intercept slope: -4, Y-intercept : -9
Mandarinka [93]

Answer:

y = -4x - 9

Step-by-step explanation:

Use slope intercept form, y = mx + b, where m is the slope and b is the y intercept.

Since we are already given the slope and y intercept, we just have to plug them into the equation to find the equation:

y = mx + b

y = -4x - 9

So, y = -4x - 9 is the equation of the line in slope intercept form

4 0
3 years ago
What is the approximate lateral surface area of the cylinder?<br> 9 cm<br> 2 cm
miss Akunina [59]

Answer:

138 is closest to the  Lateral surface which is 113.097

Step-by-step explanation:

5 0
3 years ago
xpress 8/(1 - 2x)2 as a power series by differentiating the equation below. What is the radius of convergence? 4 (1 - 2x) = 4(1
poizon [28]

Recall that for |<em>x</em>| < 1, we have

\dfrac1{1-x}=\displaystyle\sum_{n=0}^\infty x^n

Replace <em>x</em> with 2<em>x</em>, multiply 4, and call this function <em>f</em> :

f(x)=\dfrac4{1-2x}=\displaystyle4\sum_{n=0}^\infty(2x)^n

Take the derivative:

f'(x)=\dfrac8{(1-2x)^2}=\displaystyle8\sum_{n=0}^\infty n(2x)^{n-1}=\boxed{8\sum_{n=0}^\infty (n+1)(2x)^n}

By the ratio test, the series converges for

\displaystyle\lim_{n\to\infty}\left|\frac{(n+2)(2x)^{n+1}}{(n+1)(2x)^n}\right|=|2x|\lim_{n\to\infty}\frac{n+2}{n+1}=|2x|

or |<em>x</em>| < 1/2, so the radius of convergence is 1/2.

8 0
3 years ago
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