Answer:
x = (2+√10)/ 3 and x= (2-√10/3)
Step-by-step explanation:
g(x) = -3x² +4x +2
use the quadratic formula x= (-b±√b²-4ac)/2a, when g(x) = ax² +bx +c
x= [-4 ±√4²-4*(-3)*2] / 2*(-3) , solve under the square root
x= (-4 ± √16 +24) / -6 , add under the radical
x= (-4 ±√40) / -6, simplify the square root
x= (-4 ±2√10) /-6, factor -2
x= -2 (2±√10)/-2 *3, simplify -2
x= (2±√10)/3
Therefore,
x = (2+√10)/ 3 and x= (2-√10/3)
Answer:
It is (A) 4 congruent faces
Step-by-step explanation:
Easy to see how its the Base sides
-Hope it helped
9y^3-y^2 is a required answer
As 
, the 
term will converge to 0, so the limit is 2 (B).
