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Artemon [7]
3 years ago
15

(Please help its due in 5 min!!!!)A study was designed to determine the relationship between driving speed and gas consumption f

or new lightweight sports cars. What are the independent and dependent variables for this study? A. The independent variable is the driving speed, and the dependent variable is the weight of the cars. B. The independent variable is the driving speed, and the dependent variable is the gasoline consumption. C. The independent variable is the gasoline consumption, and the dependent variable is the driving speed. D. The independent variable is the weight of the cars, and the dependent variable is the driving speed.
Mathematics
2 answers:
S_A_V [24]3 years ago
6 0
B. The independent variable is the driving speed, and the dependent variable is the gasoline consumption.

Gasoline consumption will either increase or decrease based on the driving speed of the car.

The weight of the car is not essential in determining the relationship between driving speed and gas consumption.

Crank3 years ago
6 0
The answer is B the independent variable is the driving speed and the dependent variable is the gasoline consumption. <span />
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Is it rational or irrational?​
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It is irrational

Step-by-step explanation:

It is irrational because root 3 is irrational

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3 years ago
Como cálculo el área de las figuras geometrícas porfa para una persona de 5to ​
Ganezh [65]

Answer:

Se calcula sumando todos los lados (siempre y cuando tengan las mismas unidades). El área de una figura de dos dimensiones se calcula contando el número de cuadrados que pueden cubrir la figura.

Step-by-step explanation:

5 0
3 years ago
The lengths of pregnancies are normally distributed with a mean of 268 days and a standard deviation of 15 days.
Zarrin [17]
Let the lengths of pregnancies be X
X follows normal distribution with mean 268 and standard deviation 15 days
z=(X-269)/15

a. P(X>308)
z=(308-269)/15=2.6
thus:
P(X>308)=P(z>2.6)
=1-0.995
=0.005

b] Given that if the length of pregnancy is in lowest is 44%, then the baby is premature. We need to find the length that separates the premature babies from those who are not premature.
P(X<x)=0.44
P(Z<z)=0.44
z=-0.15
thus the value of x will be found as follows:
-0.05=(x-269)/15
-0.05(15)=x-269
-0.75=x-269
x=-0.75+269
x=268.78
The length that separates premature babies from those who are not premature is 268.78 days
8 0
3 years ago
What is the area of a square with side lengths of 3/5 units?
34kurt

Answer: 1/6

Step-by-step explanation:

6 0
3 years ago
Is (2, 5) a solution to the set of the following equations: 3x + 7y = 41 and -2x – 4y = -24?
jeyben [28]
Yes, (2,5) is a solution to the equations

5 0
3 years ago
Read 2 more answers
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