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marysya [2.9K]
3 years ago
6

During speciation, when do two groups become recognized as separate species? A. when they look different. B. When they are separ

ated by an isolation barrier. C. When they cannot interbreed. D. When they are both herbivores.
Biology
1 answer:
nevsk [136]3 years ago
6 0
The answer is C (when they cannot interbreed) because when the new species cannot have offspring with the old species, they do not mix traits.
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Which describes the reproduction of plants?
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Asexual reproduction that produces a zygote
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If all 5' and 3' splice sites were always used to process the pre-mRNA into mRNA, how many possible distinct mRNA sequences woul
lord [1]

The question lacks the diagram. The diagram has been attached below.

Answer:

1.

Explanation:

Exons may be defined as the coding region of the RNA whereas introns are the non coding region of the RNA. The introns must be removed out from the RNA to makes it functional molecule.

The splicing of the given molecule results in the formation of single mRNA. The 1 splicing of the introns remove intron A whereas the second splicing results in the removal of intron B. The functional mRNA consists of the mRNA with exon 1,2 and 3.

Thus, the answer is 1.

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4 years ago
Que es el significado de la palabra axiológica ?
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<span>Axiológico es todo lo que se refiere a un concepto de valor o que constituye una axiología, es decir, los valores predominantes en una determinada sociedad.</span>
6 0
3 years ago
Calculate the final concentration of BSA in the problems below using the formula
Rudiy27

Answer:

A. C_2=1.5\frac{mg}{mL}

B. C_2=0.075\frac{mg}{mL}

C. C_2=0.01\frac{mg}{mL}

D. C_2=0.001\frac{mg}{mL}

Explanation:

Hello.

In this case, we must compute the final concentration in all the cases so we solve for it in the given equation:

C_2=\frac{C_1V_1}{V_2}

Thus, we proceed as follows:

A. Here, the final diluted solution includes the 300 μL of the 5 mg/ml-BSA and the 700 μL of TBS.

C_2=\frac{300\mu L*5\frac{mg}{mL} }{(300+700)\mu L}\\\\C_2=1.5\frac{mg}{mL}

B. Here, the final diluted solution includes the 50 μL of the 1.5 mg/ml-BSA, the 450 μL of water and the 500 μL of TBS.

C_2=\frac{50\mu L*1.5\frac{mg}{mL} }{(50+450+500)\mu L}\\\\C_2=0.075\frac{mg}{mL}

C. Here, the final diluted solution includes the 10 μL of the 1 mg/ml-BSA and the 990 μL of TBS.

C_2=\frac{10\mu L*1\frac{mg}{mL} }{(10+990)\mu L}\\\\C_2=0.01\frac{mg}{mL}

D. Here, the final diluted solution includes the 10 μL of the 0.1 mg/ml-BSA and the 990 μL of TBS.

C_2=\frac{10\mu L*0.1\frac{mg}{mL} }{(10+990)\mu L}\\\\C_2=0.001\frac{mg}{mL}

Best regards.

7 0
3 years ago
What do we refer to when we separate things into groups based on their common characteristics?
sashaice [31]

Answer: Taxonomy is the process of classifying organisms based on similarities.

Explanation:

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