The average is 105.5. To find the average, you have to add up all numbers, 63+148=211. Now you have to divide by how many numbers there are, 211÷2=105.5
60<span>cm²
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-xo Cote♥
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Since it's a sample size, we use x, as the mean and s= standard deviation
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Given: x =27, s = 2 and total sample = 32.
Probability that a recruit is at least 31 years old?
Let's calculate the Z score :
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X - x 31 - 27
Z = ----------- → Z = -------- → Z = 2 (now look up in the Z score table,
s 2
Area (Z=2) =0.9772 , but Z ≥ 2 (at least) , then :
Area (Z≥2) = Area (Z≤ - 2) = 0.0228
P(≥31)= 0.0228
