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ZanzabumX [31]
2 years ago
10

Joeli has 10 quarters. She wants to buy postcards to mail to her friends. Each postcard costs 2 quarters. How many postcards can

she buy?
Mathematics
2 answers:
enot [183]2 years ago
6 0
5 postcards
I got the answer by dividing
hope it helped
Arada [10]2 years ago
3 0
5 post cards because its 10 divided by 2
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Graph the following inequality. Then click to show the correct graph. x < -1
docker41 [41]

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

x < -1

The solution is the interval ----> (-∞,-1)

All real numbers less than -1

On a number line the solution is the shaded area at the left of x=-1 (open circle)

using a graphing tool

see the attached figure

8 0
3 years ago
What is the quotient of (2x3 – 29x + 13) ÷ (x + 4)?
sleet_krkn [62]

9514 1404 393

Answer:

  C.  2x^2 -8x +3 +1/(x +4)

Step-by-step explanation:

Synthetic division is useful for finding the quotient. Or, you can use polynomial long division. The result is the same, but synthetic division requires less writing.

7 0
2 years ago
How do you find the original price after a discount. The sales price is 55.50 and the percent of discount is 75%.
Arte-miy333 [17]
Well first we know that 55.50 is 25% so I guess multiply it by 3 to get the full price equalling nearly 166 which is closest to 165, so that’d be my answer. Sorry if wrong.
6 0
2 years ago
Read 2 more answers
What is the area of the regular octagon below?
pishuonlain [190]
9 plus How many sides nine times
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3 years ago
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P(X&lt; ) 1-P(X&gt; ) A softball pitcher has a 0.626 probability of throwing a strike for each curve ball pitch. If the softball
Mashutka [201]

Answer:

19.49% probability that no more than 16 of them are strikes

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 30, p = 0.626

So

\mu = E(X) = np = 30*0.626 = 18.78

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{30*0.626*0.374} = 2.65

What is the probability that no more than 16 of them are strikes?

Using continuity correction, this is P(X \leq 16 + 0.5) = P(X \leq 16.5), which is the pvalue of Z when X = 16.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{16.5 - 18.78}{2.65}

Z = -0.86

Z = -0.86 has a pvalue of 0.1949

19.49% probability that no more than 16 of them are strikes

7 0
2 years ago
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