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Talja [164]
3 years ago
9

Find a polynomial of degree 2 with real number coefficients and zero 3-2i

Mathematics
1 answer:
marissa [1.9K]3 years ago
4 0
Complex roots occur as conjugates so the other root is 3 + 2i

so we have  the factored form 

(x - (3 - 2i)(x - (3 + 2i)

= (x - 3 + 2i)(x - 3 - 2i)

= x^2 -3x - 2ix - 3x + 9 + 6i + 2ix - 6i- 4i^2

=  x^2 -6x + 9 + 4

= x^2 - 6x + 13   Answer
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Help me please!! i beg
SIZIF [17.4K]

Eat the Legendry Fruit: And play King legcy

Step-by-step explanation:

5 0
2 years ago
How many real-number solutions does the equation have?
nevsk [136]
If the discriminant is negative no real solution exists.
If the discriminant is equal to 0 only one real solution exists.
If the discriminant is positive 2 real solutions exist.
The discriminant:
D = b² - 4 a c
1 ) - 7 x² + 6 x + 3 = 0
D = 6² - 4 · ( - 7 ) · 3 = 36 + 84 = 120  > 0
Answer: b) two solutions
2 ) - 8 x² - 8 x - 2 = 0
D = ( - 8 )² - 4 · ( - 8 ) · ( - 2 ) = 64 - 64 = 0
Answer: a ) one solution
3 0
3 years ago
Please help solve with work
sergey [27]
X-4y=28
8x+4y=8
---------------
9x=36→x=4
4-4y=28→y=6
—-----------------------------------------------------------
y-5=x
4(y-5)-y=4
4y-20-y=4
3y=24
y=8
x8-5=3
4 0
3 years ago
The difference of the squares of two positive consecutive even integers is 44 find the integers use the fact that if X represent
TiliK225 [7]

Answer:

The 2 integers are 10 and 12

Step-by-step explanation:

Translate it into english

"The difference (some subtraction) of the squares of two positive consecutive integers (x^2 and (x+2)^2) is (=) 44 (44)"

this means the following:

(x+2)^2-x^2=44

solve for x to find the smaller integer

first, expand

(x^2+4x+4)-x^2=44

x^2+4x+4-x^2=44

4x+4=44

4x=40

x=10\rightarrow x+2=10+2=12

The 2 integers are 10 and 12

3 0
3 years ago
Solve.<br><br> j – (–14) = –20<br> a. -34<br> b.34<br> c.6<br> d.-6<br> Which one?
laiz [17]
The correct answer is A) -34. Hope this helps.
4 0
3 years ago
Read 2 more answers
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