All categories

3 years ago

Find a polynomial of degree 2 with real number coefficients and zero 3-2i

1 answer:

4 0

Complex roots occur as conjugates so the other root is 3 + 2i

so we have the factored form

(x - (3 - 2i)(x - (3 + 2i)

= (x - 3 + 2i)(x - 3 - 2i)

= x^2 -3x - 2ix - 3x + 9 + 6i + 2ix - 6i- 4i^2

= x^2 -6x + 9 + 4

= x^2 - 6x + 13 Answer

You might be interested in

How many numbers are equal to the sum of two odd, one digit numbers?

JulijaS [17]

2,4,6,8,10,12,14,16,18

8 0

3 years ago

Can someone please please help with these questions?

wolverine [178]

The answer to number seven is EDF!

5 0

3 years ago

Please help! the question is in the attarchment!

DaniilM [7]

Answer:

1000( l + b)

Step-by-step explanation:

2(500l + 500b)

=500 (2(l+b))

=1000

8 0

3 years ago

The average score of all pro golfers for a particular course has a mean of 70 and a standard deviation of 3.0 (Think of these as

bija089 [108]

Answer:

0.477 is the probability that the average score of the 36 golfers was between 70 and 71.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 70

Standard Deviation, σ = 3

Sample size, n = 36

Let the average score of all pro golfers follow a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(score of the 36 golfers was between 70 and 71)

$\text{Standard error of sampling} = \displaystyle\frac{\sigma}{\sqrt{n}} = \frac{3}{\sqrt{36}} = \frac{1}{2}$

$P(70 \leq x \leq 71) = P(\displaystyle\frac{70 - 70}{\frac{3}{\sqrt{36}}} \leq z \leq \displaystyle\frac{71-70}{\frac{3}{\sqrt{36}}}) = P(0 \leq z \leq 2)\\\\= P(z \leq 2) - P(z \leq 0)\\= 0.977 - 0.500 = 0.477= 47.7\%$

$P(70 \leq x \leq 71) = 47.7\%$

0.477 is the probability that the average score of the 36 golfers was between 70 and 71.

8 0

3 years ago

Tìm x a,(2x+3x)^2-4x^2=10 b,(x+2)^-(x-2)(x+1)=3 c,(2x+3)^-4(x-1)^2=0

mash [69]

Answer:

Step-by-step explanation:

7 0

3 years ago