Find a polynomial of degree 2 with real number coefficients and zero 3-2i

1 answer:

4 0

Complex roots occur as conjugates so the other root is 3 + 2i

so we have the factored form

(x - (3 - 2i)(x - (3 + 2i)

= (x - 3 + 2i)(x - 3 - 2i)

= x^2 -3x - 2ix - 3x + 9 + 6i + 2ix - 6i- 4i^2

= x^2 -6x + 9 + 4

= x^2 - 6x + 13 Answer

You might be interested in

The difference of 10 and the product of n and 2 is 4 which operation models this

vagabundo [1.1K]

Answer:

10 - 2n - 4

Step-by-step explanation:

The product of n and 2 is 2n.

Then 10 - 2n is the difference of 10 and the product of n and 2.

In conclusion, we have:

10 - 2n - 4

3 0

3 years ago

Find each angle or arc measure

Triss [41]

To find arc WY:
360 - 156 - 86
arc WY = 118

To find angle WXY
118 / 2 = 59 degrees

4 0

2 years ago

Please help!! First correct answer = branliest!! Factor the trinomial: x^2−4x+3

PtichkaEL [24]

Look at the attached picture⤴⤴⤴

Hope this will help u...

7 0

3 years ago

Read 2 more answers

Point T has coordinates (10,20). To calculate the coordinates of point T′ in the image,

Hatshy [7]

Answer: $T'(18,36)$

Step-by-step explanation:

For this exercise it is important to know the definition of "Dilation".

A Dilation is defined as a transformation in which the Image (The figure obtained after the transformation) and the Pre-Image (The original figure before the transformation) have the same shape but have different sizes.

If the Dilation is centered at the origin, and knowing the scale factor of $\frac{9}{5}$ , you need to multiply each coordinate of the point T by the scale factor in order to find the coordinates of the Image T'.