Please help me with these questions

In NEED OF HELP! SO Frustrating!

vitfil [10]

ja, yo is correct, just expand that formula with your calculator

each one is 5% bigger than pevious

each one=previous+previous*5%

each one=previous*1+previous*0.05

each one=previous*(1+0.05)

each one is 1.05 times of previous

so after n years, if today year size is P then

$A=P(1.05)^n$

A=final size

so ya, after 18 years, n=18 so you get

$A=859(1.05)^{18}$

A=2067.29 microliters

6 0

4 years ago

X -5x -14=0 quadratic formula

Oksanka [162]

No its a negitive number one x minus five x's equal -14

8 0

3 years ago

A researcher reports survey results by stating that the standard error of the mean is 25 the population standard deviation is 40

bezimeni [28]

Answer:

a) A sample of 256 was used in this survey.

b) 45.14% probability that the point estimate was within ±15 of the population mean

Step-by-step explanation:

This question is solved using the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .