Problem 2
Plot point L anywhere that isn't on segment JK. Draw a line through point L. I find it helps to make the lines parallel.
Next, use a compass to measure the width of segment JK. Keeping this same width, transfer the nonpencil end of the compass to point L. Draw an arc that crosses the line through L.
Mark this intersection point M. Lastly, use a pen or marker to form segment LM and erase everything else of that line.
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Problem 3
The ideas of the previous problem will be used here. We copied segment JK to form congruent segment LM. So JK = LM.
The same steps will be used to form segment GN where GN = EF. In other words, segment GN is a perfect copy of segment EF.
If you repeat these steps again, you'll get another segment of the same length. This segment goes from point N to point H. So NH = GN = EF
Then we can say,
GH = GN + NH
GH = EF + EF
GH = 2*EF
He pays $780 for the television set.
1200*.35=420
1200-420=780
Nonagon - 9 sides
Sum of interior angle of a polygon is (n-2)180 = x
N is the number of sides, so when you plug in 1260 for x, you get 9 for n
Answer:
3+37=40
3/40×1200=90kg
37÷40×1200=1110kg
Step-by-step explanation:
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