Answer: find the third value when two values
The perimeter of ΔABC is 13 cm
Step-by-step explanation:
m∠B = 33° is the answer.
<u>Step-by-step explanation:</u>
If two triangles ΔABC and ΔMOP are similar, then their corresponding angles are congruent.
In any triangle, sum of the measure of the angles add up to 180°.
∠A+ ∠B+ ∠C = 180°
∠A ≅ ∠M
∠B ≅ ∠O
∠C ≅ ∠P
So we can add as,
∠A + ∠B+ ∠P = 180°
45° + ∠B + 102° = 180°
∠B + 147° = 180°
∠B = 180° - 147° = 33°
The value of the given expression after addition is 199 and this can not written as a mixed number in the simplest form.
According to the question,
We have the following expression:
212+(-13)
Now, we know that the multiplication of one negative and one positive integers is always positive.
So, we have the following expression:
212-13
199
Now, this number is whole number and it can not be written as a mixed number. It could only have been written as a mixed number when the result would have been in a fraction.
Hence, the value of the given expression after addition is 199 and this can not written as a mixed number in the simplest form.
To know more about addition here
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