Multiply first equaton by -1 and add to first
-2x+y=7
<u>4x-y=-4 +</u>
2x+0y=3
2x=3
divide 2
x=3/2
sub
2x-y=-7
2(3/2)-y=-7
3-y=-7
minus 3
-y=-10
negative 1 times both sides
y=10
(3/2,10)
(1.5,10)
B is ansre
What is the upper quartile, Q3, of the following data set? 54, 53, 46, 60, 62, 70, 43, 67, 48, 65, 55, 38, 52, 56, 41
scZoUnD [109]
The original data set is
{<span>54, 53, 46, 60, 62, 70, 43, 67, 48, 65, 55, 38, 52, 56, 41}
Sort the data values from smallest to largest to get
</span><span>{38, 41, 43, 46, 48, 52, 53, 54, 55, 56, 60, 62, 65, 67, 70}
</span>
Now find the middle most value. This is the value in the 8th slot. The first 7 values are below the median. The 8th value is the median itself. The next 7 values are above the median.
The value in the 8th slot is 54, so this is the median
Divide the sorted data set into two lists. I'll call them L and U
L = {<span>38, 41, 43, 46, 48, 52, 53}
U = {</span><span>55, 56, 60, 62, 65, 67, 70}
they each have 7 items. The list L is the lower half of the sorted data and U is the upper half. The split happens at the original median (54).
Q3 will be equal to the median of the list U
The median of U = </span>{<span>55, 56, 60, 62, 65, 67, 70} is 62 since it's the middle most value.
Therefore, Q3 = 62
Answer: 62</span>
The theoretical answer for the following question provided above would be found if you study
Answer: I'd go with C
Step-by-step explanation:
Answer:
3, and b
Step-by-step explanation:
1. x =3
Because you have 3 little squares for one x
2. x= -12
b) 15+6=21
