Answer:
Step-by-step explanation:
4^3 ⋅ 4^4 ⋅ 4^8 ÷ 4^5 . 4
64 . 256 . 65536 ÷ 1024 . 4
1073741824 ÷ 4096
=262,144
Answer:
X is five, 100% :D
Step-by-step explanation:
Answer:
k = 96/7
Step-by-step explanation:
The answer would be rational.
Stay safe!! <3
Answer:
The 99% confidence interval for the proportion of the population who are obese is (0.25, 0.282)
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
![\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}](https://tex.z-dn.net/?f=%5Cpi%20%5Cpm%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D)
In which
z is the zscore that has a pvalue of
.
For this problem, we have that:
![n = 5000, \pi = 0.266](https://tex.z-dn.net/?f=n%20%3D%205000%2C%20%5Cpi%20%3D%200.266)
99% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
![\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.266 - 2.575\sqrt{\frac{0.266*0.734}{5000}} = 0.25](https://tex.z-dn.net/?f=%5Cpi%20-%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D%20%3D%200.266%20-%202.575%5Csqrt%7B%5Cfrac%7B0.266%2A0.734%7D%7B5000%7D%7D%20%3D%200.25)
The upper limit of this interval is:
![\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.266 + 2.575\sqrt{\frac{0.266*0.734}{5000}} = 0.282](https://tex.z-dn.net/?f=%5Cpi%20%2B%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D%20%3D%200.266%20%2B%202.575%5Csqrt%7B%5Cfrac%7B0.266%2A0.734%7D%7B5000%7D%7D%20%3D%200.282)
The 99% confidence interval for the proportion of the population who are obese is (0.25, 0.282)