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DedPeter [7]
3 years ago
15

There were 2 yellow straws and 3 red how many red in 30 ​

Mathematics
1 answer:
oee [108]3 years ago
4 0

Answer:

30 yellow straws and 45 red straws

30:45

Step-by-step explanation:

Make a ratio:

2:3, 2 being the yellow straw and 3 being the red straws

They are now asking how many red if there are 30 yellow straws

2:3 = 30:x

You could either cross multiply or simply do 30 ÷ 2 = 15 then 15 × 3 = 45. Your answer is 45

<u>Cross </u><u>multiplying</u>

2x = 90

90 ÷ 2 = 45

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Right triangle

Step-by-step explanation:

7^2 + 6^2 = c^2

49 + 36 = c^2

85 = c^2

c = 9.22

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3 years ago
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Step-by-step explanation:

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Step-by-step explanation:

8 0
3 years ago
Which simplifications of the powers of i are correct?
OleMash [197]

The correct simplifications of powers of i are:

a. i^27=−i

d. i^8=1

e. i^5=i

Step-by-step explanation:

We know that

i^2=-1\\i^3=-i\\i^4=1

We can use the smaller powers of i to solve the larger powers.

a. i^27=−i

i^{27}\\={i^{24}}.i^3\\={i^{4*6}}.-i\\=(i^4)^6.-i\ \ \ \ As\ we\ know\ i^4=1\\=(1)^6.-i\\=1*-i\\=-i

b. i^28=i

i^{28}\\=i^{4*7}\\=(i^4)^7\\=(1)^7\\=1

c. i^14=1

i^{14}\\=i^{12}.i^2\\=(i^{4*3}).i^2\\=> i^2=-1\\=(i^4)^3.-1\\=(1)^3*-1\\=-1

d. i^8=1

i^8\\=i^{4*2}\\=(i^4)^2\\=(1)^2\\=1

e. i^5=i

i^5\\=i^{2*2*1}\\=i^2*i^2*i\\=(-1)(-1)(i)\\=i

Hence,

The correct simplifications of powers of i are:

a. i^27=−i

d. i^8=1

e. i^5=i

Keywords: Imaginary units, Iota

Learn more about imaginary units at:

  • brainly.com/question/8806598
  • brainly.com/question/8805387

#LearnwithBrainly

6 0
3 years ago
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