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makkiz [27]
3 years ago
9

What will be the measure of exterior angle of regular pentagon give reason of you answer

Mathematics
1 answer:
xxMikexx [17]3 years ago
4 0

Answer and Step-by-step explanation:

We~know~that~a~pentagon~has~5~sides. So, to~find~ each~exterior~angle~of~a~regular~pentagon,we'll~have~to~use~the~formula which~is:

\frac{350}{number~of~sides}

Now,~that~we~know~to~use~the~formula~let's~answer~your~question.

\frac{360}{5}= 72

Now,72~is~the~angle~for~each~exterior~angle.~To~check~whether~it's correct~multiply~72~by~5~you'll~get~it~as~360.~So~it's~the~correct~answer!

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URGENT!!!!
zhannawk [14.2K]

Answer:

Write a system of equations

Step-by-step explanation:

2x + y = 15

3x - y = 20

5x = 35

x = 7

2(7) + y =15

y = 1

5 0
3 years ago
Can someone plz help me I bed u
ycow [4]

Answer:

32

Step-by-step explanation:

area of a triangle is bxhx1/2

8x8 is 64

and then divide by 2

64/2=32

8 0
3 years ago
Someone who is good with algebra i equations and inequalities?
guajiro [1.7K]
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5 0
4 years ago
Please Hurry ...Which expression is equivalent to
swat32

Answer:

\huge\boxed{\sf \frac{160rs^5}{t^6}}

Step-by-step explanation:

\sf 5r^6t^4 ( \frac{4r^3s^tt^4}{2r^4st^6} ) ^5

Using rule of exponents \sf a^m/a^n = a^{m-n}

\sf 5r^6t^4 ( 2 r^{3-4} s^{2-1}t^{4-6})^5\\5r^6t^4(2r^{-1}st^{-2})^5\\5r^6t^4 * 32 r^{-5}s^5t^{-10}

Using rule of exponents \sf a^m*a^n = a^{m+n}

\sf 160 r^{6-5}s^5t^{4-10}

\sf 160 rs^5 t^{-6}

To equalize the negative sign, we'll move t to the denominator

\sf \frac{160rs^5}{t^6}

8 0
3 years ago
What are the coordinates of the vertex of the parabola described by the equation below? y = -7(x - 4)2 - 5
pochemuha
To get the vertex of the parabola we proceed as follows;
y=-7(x-4)^2-5
The above can be written as:
y=-7x^2+56x-117
The values of a,b and c are:
a=-7, b=56 and c=-117
x=-b/(2a)
x=-56/(-7*2)=4
but;
y=-7x^2+56x-117
y=-7(4)^2+56(4)-117
y=-5
Thus;
x=4 and y=-5
The vertex will be at point (4,-5)


7 0
4 years ago
Read 2 more answers
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