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Lunna [17]
3 years ago
11

What is the sum or difference of 3x ^ 8 - 7x ^ 8

Mathematics
1 answer:
Nina [5.8K]3 years ago
4 0
............................................................4x^8

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If x = 3 and y = -2, what is the value of the expression x^3-2xy^2?
Nana76 [90]

Answer:

3

Step-by-step explanation:

The expression is x^3-2xy^2. To find the value, substitute the values x = 3 and y =-2 then follow order of operations.

x^3-2xy^2\\3^3 -2(3)(-2)^2\\27 -2(3)(4)\\27 - 24\\3

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3 years ago
What is the sum of this infinite series? 100+60+36+(108/5)
fomenos
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8 0
4 years ago
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nydimaria [60]

Answer:

No question!

Step-by-step explanation:

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2 years ago
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3 years ago
You are to give an injection of a drug. The dosage is 0.4 mg per kilogram of bod The concentration of the drug in vial is listed
shusha [124]

Answer:

We inject 60.9628 milliliters of dosage.

Step-by-step explanation:

Given : You are to give an injection of a drug. The dosage is 0.4 mg per kilogram of bod The concentration of the drug in vial is listed as 500 ug/ml. The patient's chart Hosts weight as 168 pounds.

To find : How many milliliters (= cc) are you to inject?

Solution :

We know that,

1 pound = 0.453592 kg,

Patient's weight = 168  pounds

Patient's weight in kg =168\times 0.453592=76.203456  kg

The dosage is 0.4 mg per kilogram of bod.

So, dosage of patient weight = 0.4 \times 76.2035\ mg = 30.4814\ mg

We know,  1 micro gram = 0.001 mg

Concentration of drug is given by,

500\ \text{micro grams/ml}= 500\times 0.001\ \text{mg/ml} = 0.5\ \text{mg/ml}

Now we are supposed to find milliliters inject,

So, milliliters of dosage required to inject is

d= \frac{30.4814}{0.5} = 60.9628

Therefore, We inject 60.9628 milliliters of dosage.

3 0
4 years ago
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