Question

Help!

Answer 1

Answer: A

Step-by-step explanation:

Let the first odd integer = x

Let the second odd integer = (x+2)

This is because adding 2 to x makes it an odd integer. If 1 is added, it would become an even integer.

Let the third odd integer = (x+2)+2

= (x+4)

The sum of the first, two times the second and three times the third is written as

x + 2(x+2) + 3(x+4) = 82 (open the bracket)

x + 2x+ 4+ 3x + 12 = 82 (collect like terms)

x + 2x + 3x + 4 +12 = 82

6x + 16 =82 (this is the mathematical translation)

6x = 82 - 16

6x = 66

Divide both sides by 6

6x/6 = 66/6

x = 11

The first odd integer= 11

The second odd integer = x + 2

= 11 + 2

= 13

The third odd integer = x + 4

= 11+4

= 15

The consequtive odd integers are 11, 13 and 15