Answer: A
Step-by-step explanation:
Let the first odd integer = x
Let the second odd integer = (x+2)
This is because adding 2 to x makes it an odd integer. If 1 is added, it would become an even integer.
Let the third odd integer = (x+2)+2
= (x+4)
The sum of the first, two times the second and three times the third is written as
x + 2(x+2) + 3(x+4) = 82 (open the bracket)
x + 2x+ 4+ 3x + 12 = 82 (collect like terms)
x + 2x + 3x + 4 +12 = 82
6x + 16 =82 (this is the mathematical translation)
6x = 82 - 16
6x = 66
Divide both sides by 6
6x/6 = 66/6
x = 11
The first odd integer= 11
The second odd integer = x + 2
= 11 + 2
= 13
The third odd integer = x + 4
= 11+4
= 15
The consequtive odd integers are 11, 13 and 15
