I hope this is right but:
Let n=number of full time employees
260<=20+n*40
260-20<=N*40
240<=n*40
n>=240/40
n>=6 full time employees
which means he would have to hire at least 6 or more fully time employees
Though I'm not sure if the attached file is the graph you are looking for
The smallest 3 common multiples of 2 and 3 are 6, 12, and 18 .
The smallest 3 common multiples of 3 and 6 are also 6, 12, and 18 .
Answer:
see below
Step-by-step explanation:
— 7x — бу = — 15
To find the x intercept set y = 0 and solve for x
-7x - 0 = -15
-7x= -15
Divide by -7
-7x/-7 = -15/-7
x = 15/7
The x intercept is (15/7,0)
To find the y intercept set x = 0 and solve for y
o— бу = — 15
— бу= -15
Divide by -6
— бу/-6= -15/-6
у= 5/2
The y intercept is (0,5/2)