Question

What is the value of a when (a-12)x=a+8

Answer 1

Answer:

$a=13.59,-0.59$

Step-by-step explanation:

Assuming the question is:

$(a-12)a=a+8$

We multiply and rearrange the trinomial:

$(a-12)a=a+8\\a^2-12a=a+8\\a^2-13a-8=0$

This is a quadratic equation with:

a = 1

b = -13

c = -8

We use quadratic formula to find 2 values of a:

$a^2-13a-8=0\\a=\frac{-b+-\sqrt{b^2 - 4ac} }{2a}\\a=\frac{13+-\sqrt{169 - 4(-8)} }{2}\\a=\frac{13+-\sqrt{201} }{2}\\a=13.59,-0.59$

These are the 2 values of a:

$a=13.59,-0.59$