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Bezzdna [24]
2 years ago
7

Solve for x in the equation 2x^2 - 5x + 1 =3

Mathematics
2 answers:
solniwko [45]2 years ago
5 0

Answer:

x=2.851,-0.351

Step-by-step explanation:

Given : Equation 2x^2-5x+1=3

To find : Solve for x in the equation ?

Solution :

Equation 2x^2-5x+1=3

Subtract 3 both side,

2x^2-5x+1-3=3-3

2x^2-5x-2=0

Solve by quadratic formula,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Here, a=2,b=-5,c=-2

x=\frac{-(-5)\pm\sqrt{(-5)^2-4(2)(-2)}}{2(2)}

x=\frac{5\pm\sqrt{25+16}}{4}

x=\frac{5\pm\sqrt{41}}{4}

x=\frac{5+\sqrt{41}}{4},\frac{5-\sqrt{41}}{4}

x=2.851,-0.351

Therefore, The value of x are x=2.851,-0.351

S_A_V [24]2 years ago
3 0

The answer is x plus or minus 5 minus square root 41 all over 4

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Answer:

The vertex form of the equation is y = -\frac{1}{3}( x-1)^{2} +1.

Step-by-step explanation:

You will use the equation y=a(x-h)^{2} +k to solve this parabola. (h, k) is the vertex. So, we plug this into the equation to get y= a(x - 1)^{2} +1.

Then, we substitute the point as our x and y to get -2 = 9a+1 (a lot of simplifying was done here). Then, add 2 to the right side of the equation and isolate the 9a to get 9a = 3. Finally, divide by 9 on both sides to get a=\frac{1}{3}.

Now, substitute your a back into the equation to get y = -\frac{1}{3}(x-1)^{2}+1.

This is in vertex form. If the answer is needed in standard form, simply distribute and simplify to get y = -\frac{1}{3} x^{2} +\frac{2}{3} x+\frac{2}{3}.

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3 years ago
What is q+5/9=1/6 what is q
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5 0
3 years ago
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Hi! Could you help me me out and solve these two problems? "eight less than the product of seven and xxx", and "the sum of six a
Ann [662]

Given:

The given statement are:

a. Eight less than the product of seven and x.

b. The sum of six and the product of three and d.

To find:

The expression for the given statements.

Solution:

a.

Product of 7 and x is 7×x = 7x.

Eight less than the product of seven and x is 7x - 8.

Therefore, the required expression for the statement "Eight less than the product of seven and x" is 7x-8.

b.

Product of 3 and d is 3×d = 3d.

The sum of six and the product of three and d is 6+3d.

Therefore, the required expression for the statement "The sum of six and the product of three and d" is 6+3d.

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Otrada [13]
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2 years ago
. A retailer sold 10 packs of pens in 3 days. There were 48 pens in each pack. He sold twice as many pens on Sunday than on Mond
Marizza181 [45]

Answer:

The number of pens sold on Monday is 107 pens

Step-by-step explanation:

total pack of pen sold by the retailer in 3 days =  10 packs

total number of pens in the 10 packs = 48 x 10 = 480 pens

let the number of pens sold on Monday = x

let the number of pens sold on Sunday = y

let the number of pens sold on Tuesday = z

He sold twice as many pens on Sunday than on Monday

y = 2x ------equation (1)

He sold 55 pens fewer on Tuesday than on Sunday

y = z + 55 ------equation (2)

total number of pens sold in the three days

y + z + x = 480  ------equation (3)

from equation (1) make x the subject of the formula

x = y/2

from equation (2) make z the subject of the formula

z = y - 55

substitute the value of x, and z into equation (3)

y + y/2 + y - 55 = 480

2y + y/2 = 480 + 55

5y/2 = 535

5y = 535 x 2

5y = 1070

y = 1070 / 5

y = 214

The number of pens sold on Monday is:

x = y / 2

x = 214 / 2

x = 107 pens

Thus, the number of pens sold on Monday is 107 pens

5 0
3 years ago
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