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Bezzdna [24]
3 years ago
7

Solve for x in the equation 2x^2 - 5x + 1 =3

Mathematics
2 answers:
solniwko [45]3 years ago
5 0

Answer:

x=2.851,-0.351

Step-by-step explanation:

Given : Equation 2x^2-5x+1=3

To find : Solve for x in the equation ?

Solution :

Equation 2x^2-5x+1=3

Subtract 3 both side,

2x^2-5x+1-3=3-3

2x^2-5x-2=0

Solve by quadratic formula,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Here, a=2,b=-5,c=-2

x=\frac{-(-5)\pm\sqrt{(-5)^2-4(2)(-2)}}{2(2)}

x=\frac{5\pm\sqrt{25+16}}{4}

x=\frac{5\pm\sqrt{41}}{4}

x=\frac{5+\sqrt{41}}{4},\frac{5-\sqrt{41}}{4}

x=2.851,-0.351

Therefore, The value of x are x=2.851,-0.351

S_A_V [24]3 years ago
3 0

The answer is x plus or minus 5 minus square root 41 all over 4

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If IQ scores are normally distributed with a mean of 100 and a standard deviation of 5, what is the probability that a person se
notsponge [240]

Answer:

2.28% probability that a person selected at random will have an IQ of 110 or higher

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 100, \sigma = 5

What is the probability that a person selected at random will have an IQ of 110 or higher?

This is 1 subtracted by the pvalue of Z when X = 110. So

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