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Art [367]
4 years ago
12

Nadia says the hypotenuse of this right triangle has a length of 73 because the Pythagorean theorem states that (28 + 45) square

d = 73 squared.
3 squares are positioned to form a right triangle. The small square is labeled 28, medium square is 45, and large square is not labeled.

Which best describes Nadia’s solution
The answer could be
A:She is correct because she applied the Pythagorean theorem properly and her arithmetic is accurate.
B:She is incorrect because she should have used 45 as the length of the hypotenuse.
C:She is incorrect because she should have squared each leg length and then found the sum.
D:She is correct because the hypotenuse is the longest side of the triangle.
Mathematics
2 answers:
Mariana [72]4 years ago
5 0

Answer:

Step-by-step explanation:

masya89 [10]4 years ago
4 0

Answer:

C :She is incorrect because she should have squared each leg length and then found the sum

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28 is what percent of 80
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When conducting a survey, which of the following is a reason to use a random sample?1. To make cause-and-effect connections2. To
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Answer: 2. To avoid bias

Explanation:

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Solve 8[7-(6x-6)]+6x=0.
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3 years ago
300 students in a high school freshman class are surveyed about what kinds of pets they have. Of the 300 students, 200 have a do
katrin2010 [14]

This Question is not complete

Complete Question:

300 students in a high school freshman class are surveyed about what kinds of pets they have. Of the 300 students, 200 have a dog, 180 have a cat, and 150 have a cat and a dog. Using this information, answer each of the following questions, Let D be the event that a randomly selected student has a dog and C be the event that a randomly selected student has a cat.

a . What is P(D), the probability that a student in the class has a dog?

b. What is P(C), the probability that a student in the class has a cat?

c. What is P(D and C), the probability that a student in the class has a dog and a cat?

d. What is P(D or C), the probability that a student in the class has a dog or a cat?

Answer:

a. 2/3

b) 3/5

c) 1/2

d) 19/ 15 = 1 4/15

Step-by-step explanation:

The formula for probability =

Number of possible outcomes ÷ Number of events.

Total number of Students = 300

Number of Students that have a dog = 200

Number of Students that have a cat = 180

Number of Students that have a dog and cat = 150

a. What is P(D), the probability that a student in the class has a dog?

In the question, the given data is interpreted as :

Number of possible outcomes = 200

Number of events = 300

P(D) = 200/300

= 2/3

Therefore, the probability that a student has a dog = 2/3

b. What is P(C), the probability that a student in the class has a cat?

In the question, the given data is interpreted as :

Number of possible outcomes = 180

Number of events = 300

P(D) = 180/300

= 3/5

Therefore, the probability that a student has a cat = 3/5

c. What is P(D and C), the probability that a student in the class has a dog and a cat?

In the question, the given data is interpreted as :

Number of possible outcomes = 150

Number of events = 300

P(D) = 150/300

= 1/2

Therefore, the probability that a student has a dog and cat = 1/2

d. What is P(D or C), the probability that a student in the class has a dog or a cat?

The is calculated as

P(D) + P(C)

In the above question,

P(D) is calculated as 2/3

P(C) is calculated as 3/5

Therfore, P(D or C), the probability that a student in the class has a dog or a cat is calculated as:

= 2/3 +3/5

= 19/15 = 1 4/15

7 0
3 years ago
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