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alukav5142 [94]
3 years ago
13

Write these numbers in standard notation. 3.05 x 10–3 8.92 x 106

Mathematics
2 answers:
Bad White [126]3 years ago
3 0

3.05  \times   {10}^{ - 3} =0.00305 \\8.92 \times  {10}^{6} =   8920000
Flauer [41]3 years ago
3 0

Answer:

We have been given the two numbers:

3.05 \cdot 10^{-3}

And 8.92\cdot 10^{6}

x^{-a}=\frac{1}{x^a}

10^{-3}=\frac{1}{10^3}=\frac{1}{1000}

So, 3.05 \cdot 10^{-3}=\frac{3.05}{1000}

\Rightarrow 0.00305

And 8.92\cdot 10^{6}=\frac{892}{100}\cdot {1000000}

892\cdot 10000

\Rightarrow 8920000

3.05 \cdot 10^{-3}=0.00305

8.92\cdot 10^{6}=8920000

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6 0
3 years ago
A company establishes a fund of 120 from which it wants to pay an amount,C, to any of its 20 employees who achieve a high-perfor
Leno4ka [110]

Answer:

C=120/2=60

Step by step Explanation'

To solve this problem, we will need to apply trial-and-error calculation with the binomial distribution, even though it appears like Central Limit Theorem but it's not.

For us to know the value of C , we will look for a minimum integer such that having 'n' number of high performance level of employee has the probability below 0.01.

Determine the maximum value of C, then the maximum value that C can have is 120/n

Let us represent X as the number of employees with high performance with a binomial distribution of

P =0.02( since the percentage of chance of achieving a high performance level is 2%)

n = 20 ( number of employees who achieve a high performance level)

The probability of X= 0 can be calculated

P( X= 0) = 0.98^n

P(X=0)=0.98^20

P(X=0)=0.668

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P(X=1)=0.272

P(X=2)=0.02^2*20*0.98^18

P(X=2)=0.053

Summation of P( X= 0)+ P( X= 1)+P( X= 2) will give us the value of 0.993 which is greater than 0.99( 1% that the fund will be inadequate to cover all payments for high performance.)

BUT the summation of P( X= 0)+ P( X= 1) will give the value of 0.94 which doesn't exceed the 0.99 value,

Therefore, the minimum value of integer in such a way that P(X >2) is less than 0.01 have n= 2

then the maximum value that C can have is 120/n

C=120/2=60

7 0
4 years ago
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