The integrals over B and T will be positive. Keeping $y$ fixed, $xe^x$ is strictly increasing over D as $x$ increases, so the integrals over $x$ (i.e. the bottom/top left quadrants of D) is negative but the integrals over $x>0$ are *more* positive.

The integrals over R and L are zero. If we take $f(x,y)=xe^x$ , then $f(x,-y)=f(x,y)$ , which is to say $f$ is symmetric across the $x$ -axis. For the same reason, the integral over all of D is also zero.

4 0

3 years ago

If the rate at each store is constant, which statement correctly compares the cost of a package containing 20 CDs?

svlad2 [7]

Answer:

the answer is A:

The cost at Store A is $2.00 greater than at Store B.

5 0

3 years ago

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