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2 years ago

What is 10(5)-60+5+6

Mathematics

2 answers:

diamong [38]2 years ago

7 0

10(5)-60+5+6
So, first multiple 10 by 5, 50
now we have 50-60+5+6
50-60=-10
-10+5+6
It's 1

alexgriva [62]2 years ago

5 0

Answer: 1
Simplify the expression
10(5)-60+5+6 1) Multiply 10(5)
50-60+5+6 2) 50-60
-10+5+6 3) -10+5
-5+6 4) -5+6
1 5) Answer 1

Hope this helps! :)

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I need help with this question.

devlian [24]

We can see that $a$ lies just before 0, $b$ lies between 2 and 3m and $c$ lies between 4 and 5. So, we have

$-1 < a < 0,\quad 2 < b < 3,\quad 4 < c < 5$

In particular, this implies that

$-1+4 < a+c < 0+5 \iff 3 < a+c < 5$

So, the correct order would be

$-2,\ b,\ a+c$

7 0

2 years ago

600,000+2,000+500+40+7 in standard form

attashe74 [19]

The standard form would be 602,547

3 0

2 years ago

Jake and Hakeem's rocket's flight is approximately modeled by the equation h(t) = - 12t ^ 2 + 36t + 3 where h(t) is the height i

kumpel [21]

Answer:

30m

Step-by-step explanation:

Since we are not told what to look for, we can find the maximum height reached by the rocket

Given the rocket's flight approximately modeled by the equation

h(t) = - 12t ^ 2 + 36t + 3

At maximum height dh/dt = 0

dh/dt = --24t + 36

0 = -24t + 36

24t = 36

t= 36/24

t = 1.5s

Get the max height

h(1.5) = - 12 (1.5)^ 2 + 36(1.5) + 3

h(1.5) = - 12(2.25) + 54 + 3

h(1.5) = -27 + 57

h(1.5) = 30m

Hence the maximum height reached by the rocket is 30m

8 0

2 years ago

The diagram shows a right triangle and three squares. The area of the largest square is 55 units.

Keith_Richards [23]

Answer:

Step-by-step explanation:

Well the sides of the smaller squares have to be greater than the biggest when put together.

a + b > c

So we need to find the square root of 55.

$\sqrt{55}$

≅ 7.4

Now for option A)

srt ⇒ 12 ≅3.5

srt ⇒ 43 ≅ 6.6

3.5 + 6.6 = 10.1

So option A is correct.

Option B)

srt ⇒ 14 ≅ 3.7

srt ⇒ 40 ≅ 6.3

3.7 + 6.3 = 10

So option B is also correct.

Option C)

srt ⇒ 16 = 4

srt ⇒ 37 ≅ 6.1

4 + 6.1 = 10.1

So option C is also correct.

Therefore,

all options are correct.

Hope this helps :)

6 0

3 years ago

Read 2 more answers

1. In how many ways can a committee of eight people to be formed from a group of 6 male, 5 female and 4 students if there are no

NeX [460]

Answer:

The number of ways is 6435

Step-by-step explanation:

Given

$Male = 6$

$Female = 5$

$Students = 4$

Required

Number of ways a group of 8 can be formed

Here, I'll assume each category of people are distinct:

Hence;

$Total = Male + Female + Students$

$Total = 6 + 5 + 4$

$Total = 15$

Number of ways is then calculated as follows:

$^nC_r = \frac{n!}{(n - r)!r!}$

Where

$n = 15\ and\ r = 8$

So, we have:

$^{15}C_8 = \frac{15!}{(15 - 8)!8!}$

$^{15}C_8 = \frac{15!}{7! * 8!}$

$^{15}C_8 = \frac{15 * 14 * 13 * 12 * 11 * 10 * 9 * 8!}{7!8!}$

$^{15}C_8 = \frac{15 * 14 * 13 * 12 * 11 * 10 * 9}{7!}$

$^{15}C_8 = \frac{15 * 14 * 13 * 12 * 11 * 10 * 9}{7 * 6 *5 * 4 * 3 * 2 * 1}$

$^{15}C_8 = \frac{32432400}{5040}$

$^{15}C_8 = 6435$

Hence, the number of ways is 6435

7 0

2 years ago