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gavmur [86]
3 years ago
14

What is 10(5)-60+5+6

Mathematics
2 answers:
diamong [38]3 years ago
7 0
<span>10(5)-60+5+6
So, first multiple 10 by 5, 50
now we have 50-60+5+6
50-60=-10
-10+5+6
It's 1</span>
alexgriva [62]3 years ago
5 0
Answer: 1
Simplify the expression 
10(5)-60+5+6     1)  Multiply 10(5)
50-60+5+6          2)  50-60
-10+5+6              3)  -10+5
-5+6                    4)  -5+6
1                          5)  Answer 1

Hope this helps! :)
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Are 4/16 and 0.25/2 equivalent numbers? If so, explain how they are.
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Read 2 more answers
Root 3 cosec140° - sec140°=4<br>prove that<br><br>​
Lorico [155]

Answer:

Step-by-step explanation:

We are to show that \sqrt{3} cosec140^{0} - sec140^{0} = 4\\

<u>Proof:</u>

From trigonometry identity;

cosec \theta = \frac{1}{sin\theta} \\sec\theta = \frac{1}{cos\theta}

\sqrt{3} cosec140^{0} - sec140^{0} \\= \frac{\sqrt{3} }{sin140} - \frac{1}{cos140} \\= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\

From trigonometry, 2sinAcosA = Sin2A

= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\\\=  \frac{\sqrt{3}cos140-sin140 }{sin280/2}\\=  \frac{4(\sqrt{3}/2cos140-1/2sin140) }{2sin280}\\\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{sin280}\\since sin420 = \sqrt{3}/2 \ and \ cos420 = 1/2  \\ then\\\frac{4(sin420cos140-cos420sin140) }{sin280}

Also note that sin(B-C) = sinBcosC - cosBsinC

sin420cos140 - cos420sin140 = sin(420-140)

The resulting equation becomes;

\frac{4(sin(420-140)) }{sin280}

= \frac{4sin280}{sin280}\\ = 4 \ Proved!

3 0
3 years ago
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