a gallon of milk costs $3.80 .if there are 128 ounces = 1 gallon ,how much money does an 8 ounce of milk cost?

On the scale drawing of a car, the length from bumper to bumper is 6 inches. The car’s actual length, from bumper to bumper, is

Nastasia [14]

I honestly don’t know

8 0

3 years ago

Read 2 more answers

Simplify and plz show work on a piece of paper

IrinaK [193]

●) -2 (3a - 4b)-6a + 3b
-2 (9a-7b)
●) 10 - 6a - 4y - (-2a) + 9y
10 - 6a - 13y - (-2a)
●) 9 (2x-6) - 3 (5-4x
12 (6x-11)

All I did was combine the numbers with the same variable

3 0

3 years ago

Temperature in degrees Fahrenheit is equal to 32 more than 9/5 times the temperature in degrees Celsius . One day the high tempe

bazaltina [42]

The high temperature is 35 degree celsius

<em><u>Solution:</u></em>

Given that, Temperature in degrees Fahrenheit is equal to 32 more than 9/5 times the temperature in degrees Celsius

Let "f" be the temperature in degree Fahrenheit

Let "c" be the temperature in degree celsius

Therefore,

Temperature in degrees Fahrenheit = 32 + $\frac{9}{5}$ times the temperature in degrees Celsius

$f = 32 + \frac{9}{5} \times c$

One day the high temperature in Edison. Nj was 95 degrees Fahrenheit

f = 95 ; c = ?

Substitute f = 95 in above equation

$95 = 32 + \frac{9c}{5}\\\\95=\frac{32 \times 5 +9c}{5}\\\\95 \times 5 = 160+9c\\\\475 = 160 + 9c\\\\9c = 475 - 160\\\\9c = 315\\\\c = 35$

Thus high temperature in degrees Celsius is 35 degree celsius

5 0

3 years ago

Someone help I don't know this trig question

solong [7]

Answer:

Bill is 9.80 km apart from Concert

Step-by-step explanation:

It's given in the question,

m∠B = 75°

m∠C = 45°

By triangle sum theorem,

m∠A + m∠B + m∠C = 180°

m∠A + 75° + 45° = 180°

m∠A = 180° - 120°

m∠A = 60°

By sine rule,

$\frac{\text{sin}(\angle A)}{BC}=\frac{\text{sin}(\angle C)}{AB}$

$\frac{\text{sin}(60)}{BC}=\frac{\text{sin}(45)}{8}$

BC = $\frac{8\text{sin}(60)}{\text{sin}(45)}$

= 9.80 km

Therefore, Bill is 9.80 km apart from Concert.

8 0

3 years ago

A political poll finds that 305 out of 600 (50.8%) of a random sample of likely voters are in favor of the Democrat over the Rep

madam [21]

Answer:

1)

Option A.(46.8%, 54.8%) is the correct Answer.

Since the Confidence Interval for the true proportion must contain or include ( p = 50% or 0.5 ), (46.8%, 54.8%) could be the correct 95% confidence interval (range of plausible values) for the true proportion of voters that will vote for the Democrat candidate.

2)

When a graph falls on a normal distribution, Using the mean is very good choice but when the data has extreme scores, then one should use the median instead of the mean.

Step-by-step explanation:

Given the data in the question;

Null hypothesis H₀ : p = 50% or 0.5

Alternative hypothesis Hₐ : p ≠ 50% or 0.5

given that p-value = 0.714

The p-value is large, so we can not reject Null hypothesis.

Thus, p = 50% or 0.5

Meaning that, the Confidence Interval for the true proportion must contain or include ( p = 50% or 0.5 )

Thus, Option A.(46.8%, 54.8%) is the correct Answer.

Since the Confidence Interval for the true proportion must contain or include ( p = 50% or 0.5 ), (46.8%, 54.8%) could be the correct 95% confidence interval (range of plausible values) for the true proportion of voters that will vote for the Democrat candidate.

2)

When a graph falls on a normal distribution, Using the mean is very good choice but when the data has extreme scores, then one should use the median instead of the mean.

5 0

3 years ago