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andrezito [222]
3 years ago
15

What two expressions that are equivalent to: (-4n+2/7m)-(3 5/7m-n)​

Mathematics
1 answer:
jeyben [28]3 years ago
3 0

i have no clue hahahaha

352

532221

3522

thats it haha

hfwjdiwq

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Plz help i can’t figure it out
Ivan

Answer:

-(x-10)=7

-x+10=7

-x=7-10

-x=-3

x=3

5 0
4 years ago
Read 2 more answers
Fully factorise x² + 7x+6
marin [14]

\\ {\large{\textsf{\textbf{\underline{\underline{ Question \: :}}}}}}  \\

Factorise ;

  • x² + 7x+6

\qquad\rule{120pt}{2pt}

\\ {\large{\textsf{\textbf{\underline{\underline{ Solution \: :}}}}}}  \\

\\  \sf \implies \:  {x}^{2} + 7x+6 \\

\\  \sf \implies \:  {x}^{2} + 6x + x+6 \\

\\  \sf \implies \:  x(x + 6)  +1 (x+6) \\

\\  \sf \implies \:  (x + 6)   (x+1) \\

\\  \sf \implies \:  x + 6= 0 \:\:\:\:  and\:\:\:\:  x+1=0 \\

\\  \sf \implies \:  x= 0 -6\:\:\:\:  and\:\:\:\:  x=0-1 \\

\\  \sf \implies \:  x= -6\:\:\:\:  and\:\:\:\:  x=-1 \\

\\\sf\implies\;{\underline{\boxed {\bf{ \:\:x=-6\:\: }}} }\red\bigstar \;\; \;\; \;{\underline{\boxed {\bf{ \:\:x=-1\:\: }}} }\red\bigstar \\

\\\qquad\rule{120pt}{2pt}\\

5 0
1 year ago
Read 2 more answers
Jerry has $558 to spend on dining room chairs. if each chair costs $58, does he have enough to purchase nine chairs
netineya [11]

Answer:

No because the chairs would have to be the price of $62.00

Step-by-step explanation:

divide 558 by 9

so if the chairs had been 62 dollars then he would have enough

4 0
3 years ago
- Andy wants to rent a one-bedroom apartment in Green Acres. The apartment has a monthly rent of
rjkz [21]

Answer:

$161.88

Step-by-step explanation:

1, 425 * 0.05 = 71.25 = yearly

71.25 / 12 = 5.94 = monthly

5.94 * 2 = 11.88 = for two months

11.88 + 150 = 161.88 = the amount he is expected to pay

Tell me if I'm wrong :)

8 0
3 years ago
Please help!!As soon as possible!!
pychu [463]

Answer: Their equations have different y-intercept but the same slope

Step-by-step explanation:

Since, the slope of the line passes through the points (2002,p) and (2011,q) is,

m_1 = \frac{q-p}{2011-2002} = \frac{q-p}{9}

Similarly, the slope of the line asses through the points (2,p) and (11,q) is,

m_2 = \frac{q-p}{11-2} = \frac{q-p}{9}

Since, m_1 = m_2

Hence, both line have the same slope.

Now, the equation of the line one having slope m_1 and passes through the point (2002,p) is,

y - p = \frac{q-p}{9}(x-2002)

Put x = 0 in the above equation,

We get, y = \frac{2000(p-q)}{9}+p

The y-intercept of the line one is (0, \frac{2000(p-q)}{9}+p)

Also, the equation of second line having slope m_2 and passes through the point (2,p)

y-p=\frac{q-p}{9}(x-2)

Put x = 0 in the above equation,

We get, y = \frac{2(p-q)}{9}+p

The y-intercept of the line one is (0, \frac{2(p-q)}{9}+p)

Thus, both line have the different y-intercepts.

⇒ Third option is correct.

6 0
3 years ago
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