Solving a polynomial inequation
Solving the following inequation:
(x - 8) (x + 1) > 0
We are going to find the sign both parts of the multiplication,
(x - 8) and (x + 1), have when
x < - 8
-8 < x < 1
1 < x
Then we know (x - 8) (x + 1) > 0 whenever (x - 8) (x + 1) is positive
We can see in the figure (x - 8) (x + 1) is positive when x < -8 and x > 1
Then
Answer:B
Answer:

Step-by-step explanation:
The sine of an angle is defined as the ratio between the opposite side and the hypotenuse of a given right-angled triangle;
sin x = ( opposite / hypotenuse)
The opposite side to the angle x is thus 1 unit while the hypotenuse is 3 units. We need to determine the adjacent side to the angle x. We use the Pythagoras theorem since we are dealing with right-angled triangle;
The adjacent side would be;

The cosine of an angle is given as;
cos x = (adjacent side / hypotenuse)
Therefore, the cos x would be;

Answer: the volume of a rectangular prisim with lenths (12ft , height 14 ft , and width 17 ft ) is
V=2856ft³
Use the Pythagorean theorem. The Pythagorean Theorem uses the following formula:

Plug in the known values into the equation:



Subtract both sides by 36.

Square root both sides to get b by itself.


The value of x is 8.
-6z = 72
Divide both sides by -6
-6z = 72
/-6 /-6
z = -12