All categories

3 years ago

An empty container has a mass of 0.6 kg.

Mathematics

1 answer:

jenyasd209 [6]3 years ago

8 0

There are 9 × 10^5 grains of rice in the container.

Step-by-step explanation:

Step 1: Find the mass of rice in the container.

Mass of empty container = 0.6 kg

Mass of container filled with rice = 18.6 kg

⇒ Mass of rice = 18.6 - 0.6 = 18 kg

Step 2: Find the number of grains in the container.

Mass of one grain of rice = 2 × 10^-2 g = 2 × 10^-2/10³ kg (∵ 1 kg = 1000 g)

= 2 × 10^-5 kg

⇒ Number of grains of rice = Total Mass of rice/Mass of 1 grain

= 18/2 × 10^-5

= 9 × 10^5 grains of rice

You might be interested in

Assume that 12 jurors are randomly selected from a population in which 73% of the people are Mexican-Americans. Refer to the pro

kumpel [21]

Answer:

I'm not sure if i'm correct but i'm guessing no

Step-by-step explanation:

6 0

3 years ago

A line has a slope of -13. There is a second line that passes through points (-7,-5) and (6,-4) . Would these lines be parallel

Elza [17]

<h3>Answer: The lines are perpendicular</h3>

=================================================

Work Shown:

Use the slope formula to find the slope of the line through the two given points.

m = (y2 - y1)/(x2 - x1)

m = (-4 - (-5))/(6 - (-7))

m = (-4 + 5)/(6 + 7)

m = 1/13

The slope of the line through the two given points is 1/13.

This is not equal to -13, which was the slope of the first line, so the two lines are not parallel.

However, the two lines are perpendicular because multiplying the two slope values leads to -1

(slope1)*(slope2) = (-13)*(1/13) = -1

note: It might help to think of -13 as -13/1 to help multiply the fractions.

3 0

3 years ago

Denise collects stuffed animals. The number of stuffed animals in her collection, a, after n, number of years, can be described

JulijaS [17]

Answer:

its a

Step-by-step explanation:

4 0

3 years ago

The function f(x)=−2(0.25)x+1 is shown. Select from the drop-down menus to correctly describe the end behavior of f(x).

Viktor [21]

Answer:

cos 59° = x/16

x = 16 cos 59°

x = 8.24

BC is given 23 mi

Maybe AB is needed

AB = √34² + 23² = 41 (rounded)

BC² = AB² - AC²

BC = √(37² - 12²) = 35

Let the angle is x

cos x = 19/20

x = arccos (19/20)

x = 18.2° (rounded)

See attached

Added point D and segments AD and DC to help with calculation

BC² = BD² + DC² = (AB + AD)² + DC²

Find the length of added red segments

AD = AC cos 65° = 14 cos 65° = 5.9

DC = AC sin 65° = 14 sin 65° = 12.7

Now we can find the value of BC

BC² = (19 + 5.9)² + 12.7²

BC = √781.3

BC = 28.0 yd

All calculations are rounded

6 0

3 years ago

a. Fill in the midpoint of each class in the column provided. b. Enter the midpoints in L1 and the frequencies in L2, and use 1-

Tresset [83]

Answer:

$\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1} & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7} & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}$

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795

Step-by-step explanation:

Given

See attachment for class

Solving (a): Fill the midpoint of each class.

Midpoint (M) is calculated as:

$M = \frac{1}{2}(Lower + Upper)$

Where

$Lower \to$ Lower class interval

$Upper \to$ Upper class interval

So, we have:

Class 63-65:

$M = \frac{1}{2}(63 + 65) = 64$

Class 66 - 68:

$M = \frac{1}{2}(66 + 68) = 67$

When the computation is completed, the frequency distribution will be:

Solving (b): Mean and standard deviation using 1-VarStats

Using 1-VarStats, the solution is:

$\bar x = 70.2903$

$\sigma = 3.5795$

<em>See attachment for result of 1-VarStats</em>

8 0

3 years ago