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3 years ago

Please help!! See the attachment, please!

Mathematics

1 answer:

topjm [15]3 years ago

5 0

Answer:

$946$

Step-by-step explanation:

we know that

The formula to find the sum is equal to

$S=(a1+an)n/2$

where

a1 is the first term

an is the last term

n is the number of terms

In this problem we have

$n=11$

$a1=(98-2(1))=96$

$an=(98-2(11))=76$

substitute the values in the formula

$S=(96+76)(11/2)=946$

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Step-by-step explanation:

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5(2- 7x)

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3 years ago

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Sindrei [870]

Answer:

Step-by-step explanation:

12-(-4)(-3)

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3 years ago

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C. Make n subject of the formula<br>S= n/2 [2a + (n - 1)d]<br><br>please provide your working out

yKpoI14uk [10]

Answer:

$n=\frac{4as -2ds}{(1-2ds)}$

Step-by-step explanation:

$S= \frac{n}{2 [2a + (n - 1)d]}$

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$s=\frac{n}{2 [2a + (n - 1)d] } = \frac{n}{2[2a + dn - d] }$

Simplifying the fraction by multiplying 2 throughout,

$s= \frac{n}{4a + 2dn-2d}$

Multiply $(4a + 2dn-2d)$ on both sides

$(4a + 2dn-2d)s= \frac{n}{4a + 2dn-2d} (4a + 2dn-2d)$

Cancel the $(4a + 2dn-2d)$ on the right hand side

$(4a + 2dn-2d)s= n$

Multiply s to the terms,

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Move $2dns$ to the right hand side by subtracting $2dns$ on both sides $4as + 2dns-2ds-2dns= n-2dns$

$4as -2ds= n-2dns$

On the right hand side of the equation, take out $n$

$4as -2ds= n(1-2ds)$

Divide Left hand side by $(1-2ds)$ ,

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

Please help!! See the attachment, please!​

Please help!! See the attachment, please!