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GrogVix [38]
3 years ago
14

A man starts climbing a hill every minute he ascends 20 yards but slips down 5 yards. how long he will take to ascends a pt 80 y

ards highy​?
Mathematics
1 answer:
Ivahew [28]3 years ago
7 0
It will take him 25 yards
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A food company sells salmon to various customers. The mean weight of the salmon is 44 lb with a standard deviation of 3 lbs. The
TiliK225 [7]

Correct question:

A food company sells salmon to various customers. The mean weight of the salmon is 44 lb with a standard deviation of 3 lbs. The company ships them to restaurants in boxes of 9 ​salmon, to grocery stores in cartons of 16 ​salmon, and to discount outlet stores in pallets of 64 salmon. To forecast​ costs, the shipping department needs to estimate the standard deviation of the mean weight of the salmon in each type of shipment. Complete parts​ (a) and​ (b) below.

a. Find the standard deviations of the mean weight of the salmon in each type of shipment.

b. The distribution of the salmon weights turns out to be skewed to the high end. Would the distribution of shipping weights be better characterized by a Normal model for the boxes or pallets?

Answer:

Given:

Mean, u = 44

Sd = 3

The company ships in boxes of 9, cartons of 16 and pallets of 64.

a) For the standard deviations of the mean weight of the salmon in each type of shipment, lets use the formula: \frac{s.d}{\sqrt{u}}

i) For the standard deviation of the mean weight of salmon in boxes of 9, we have:

\frac{s.d}{\sqrt{u}}

= \frac{3}{\sqrt{9}}

= \frac{3}{3} = 1

The standard deviation = 1

ii) For the standard deviation of the mean weight of salmon in cartons of 16, we have:

\frac{s.d}{\sqrt{u}}

= \frac{3}{\sqrt{16}}

= \frac{3}{4} = 0.75

Standard deviation = 0.75

iii) For the standard deviation of the mean weight of salmon in pellets of 64, we have:

\frac{s.d}{\sqrt{u}}

= \frac{3}{\sqrt{64}}

= \frac{3}{8} = 0.375

Standard deviation = 0.375

b) The distribution of shipping weights would be better characterized by a Normal model for the pallets, because regardless of the underlying distribution, the sampling distribution of the mean approaches the Normal model as the sample increases.

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4 years ago
A large concrete water pipe is being laid underground. The pipe has a diameter of 24 inches and is laid in 40 foot sections. How
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Volume=hpir^2
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h=40

v=40pi12²
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3 years ago
Can someone help me round up decimals plzz
boyakko [2]
In this situation, 0.782 would be rounded to 0.8

how to round a decimal: take the underlined number and look to the number located to the RIGHT of the underlined number, if the number to the right of the underlined number is 4 or less you leave the underlined number as is - but if the number right to underlined number is 5 or greater you round the underlined number up by one

ex. 1.83 [round to the nearest tenth]

answer: 1.80

instead of keeping the 3 [hundredth] you turn it into a 0.

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