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3 years ago

Lines that are parallel have the same slope or else no slope.

Mathematics

1 answer:

hammer [34]3 years ago

8 0

This is true, if that's what your looking for. because theyre parallel they have to same slope.

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PLEASE HELP ME ON THIS

prohojiy [21]

This is in the form mx + b
so,
g(x) = -3x - 5 + 9
-3x + 4
the b is the y-int
y-int = 4

8 0

3 years ago

Each month, Matthew gets a $25 allowance and earns $100 mowing lawns. He uses the expression 25x + 100y to keep track of his ear

allochka39001 [22]

Part A
The variables would be x and y where as the coefficients would be 25 and 100

Part B
There are two terms in the expression, those being 25x and 100y. This is because s plus or minus sign separates terms, and in this case, we only have one plus sign.

Part C
The term that represents the total earnings from mowing lawns in 100y, because the prompt says that he earns $100 mowing lawns.

4 0

3 years ago

The direction of the (slope) vector is? Given: u = Initial point (1,1) , terminal point (4,3)

irakobra [83]

Answer:

2/3

Step-by-step explanation:

Slope = y2 - y1/x2 - x1

Given

x1 = 1

y1 = 1

x2 = 4

y2 = 3

Slope = 3 - 1/4 - 1

= 2/3

8 0

4 years ago

Find missing angles

Rainbow [258]

Answer:3=37 m1=62 m2=45 m3=24

Step-by-step explanation:

7 0

3 years ago

from the top of a 120-foot high tower an air traffic controller observes an airplane on the runway at an angle of depression of

Crazy boy [7]

Data:
h (Tower height) = 120 ft
d (Distance from the base of the tower to the airplane) = ?
 $\alpha$ (Angle formed from observation of the tower to the airplane)=19º

Data: tg 19º ≈ 0.34

Note: The angle formed is tangent to the height of the tower and the distance from the base of the tower to the airplane.

Formula:
 $tg \alpha = \frac{opposite\:leg}{adjacent\:leg}$

Solving:
 $tg \alpha = \frac{opposite\:leg}{adjacent\:leg}$
$tg 19^0 = \frac{h}{d}$
$tg 19^0 = \frac{120}{d}$
$0.34 = \frac{120}{d}$
$0.34*d = 120$
$0.34d = 120$
$d = \frac{120}{0.34}$
$\boxed{\boed{d \approx 352.9\:ft}}\end{array}}\qquad\quad\checkmark$

Answer:
Distance from the base of the tower to the airplane is aproximately 352.9 ft

6 0

3 years ago