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2 years ago

Is a w2 needed to open a checking account

Mathematics

2 answers:

Ahat [919]2 years ago

6 0

No you do not if you are not employed.

Anastasy [175]2 years ago

5 0

No, you just need to verify your identity, so I mean you could use a w2 for that but its not required by any means

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If f(x)=-3x+4 and g(x)=x2, what is (g°f)(0)

Rus_ich [418]

Answer:

Step-by-step explanation:

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3 years ago

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Find the least common multiple.

vovangra [49]

Answer:

C - 3,600

Step-by-step explanation:

100 16 45 ÷ 2

50. 8. 45 ÷ 2

25. 4. 45 ÷ 2

25. 2. 45. ÷ 2

25. 1. 45. ÷ 3

25. 1. 15. ÷ 3

25. 1. 5. ÷ 5

5. 1. 1. ÷ 5

1. 1. 1

L.C.M = 2 x 2 x 2 x 2 x 3 x 3 x 5 x 5 = 3, 600

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3 years ago

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Llana [10]

Answer:

ok I will help

Step-by-step explanation:

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2 years ago

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Which of the following are solutions to the equation below?

scoundrel [369]

Answer:

The correct options for the solution values are:

$x=2\sqrt{2}-5$

$x=-2\sqrt{2}-5$

Step-by-step explanation:

Given the expression

$x^2+10x+25=8$

Subtract 25 from both sides

$x^2+10x+25-25=8-25$

Simplify

$x^2+10x=-17$

Add 25 or 5² to both sides

$x^2+10x+5^2=8$

$x^2+10x+5^2=\left(x+5\right)^2$

so the expression becomes

$\left(x+5\right)^2=8$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x+5=\sqrt{8}$

Subtract 5 from both sides

$x+5-5=2\sqrt{2}-5$

$x=2\sqrt{2}-5$

solve

$x+5=-\sqrt{8}$

Subtract 5 from both sides

$x+5-5=-2\sqrt{2}-5$

$x=-2\sqrt{2}-5$

Therefore, the solution to the equation

$x=2\sqrt{2}-5,\:x=-2\sqrt{2}-5$

Hence, the correct options for the solution values are:

$x=2\sqrt{2}-5$

$x=-2\sqrt{2}-5$

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2 years ago

A school district needs 3 teachers for every 70 children. They expect to have 14,700 children in the district next year. At this

zzz [600]

They need 18 more teachers.
Set the problem up as a ratio.
3    x
---- = -------
70    14,700

70 x = 44,100
   x = 630

The district already has 612 teachers. So, 630 - 612 = 18 more needed.

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2 years ago

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